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kolezko [41]
3 years ago
10

The complete oxidation of glucose (c6h12o6) to carbon dioxide and water in aerobic respiration consumes how many molecules of ox

ygen (o2)?
Chemistry
1 answer:
Butoxors [25]3 years ago
6 0
Answer is: 6 molecules of oxygen.
First, write down reaction for aerobic respiration:
C₆H₁₂O₆ (glucose) + 6O₆ (molecule of oxygen) → 6CO₂ (carbon-dioxide) + 6H₂O (water).
Reaction shows that one molecule of glucose react with six molecules of oxygen.
Aerobic respiration<span> requires </span>oxygen<span> to create energy.</span>
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Explain vapour pressure and surface tension What is plasma
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Surface Tension: is the attraction between liquid molecules.

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5 0
3 years ago
What is the molarity (M) of the following solutions?
Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

                                      = 27 + 3(16 + 1)

                                      = 27 + 3(17) = 27 + 51

                                      = 78 g/mole

Al(OH)_3 = 78 g/mole

Given mass= 19.2 g/mole

Mole = \frac{Given\ mass}{Molar\ mass}

Mole = \frac{19.2}{78}

Moles = 0.246

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Volume = 280 mL = 0.280 L

Molarity = \frac{0.246}{0.280)}

Molarity  = 0.879 M

Molarity  = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr​

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

Mole = \frac{235.9}{119}

Moles = 1.98

Volume = 2.6 L

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Molarity = \frac{1.98}{2.6)}

Molarity = 0.762 M

Molarity = 0.76 M

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3 years ago
3 examples of potential energy
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On headedama be prepared​
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Answer:

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yea

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What is true for two pieces of iron at the same temperature?
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<span>D. The average kinetic energy of their particles is the same.</span>
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