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kolezko [41]
3 years ago
10

The complete oxidation of glucose (c6h12o6) to carbon dioxide and water in aerobic respiration consumes how many molecules of ox

ygen (o2)?
Chemistry
1 answer:
Butoxors [25]3 years ago
6 0
Answer is: 6 molecules of oxygen.
First, write down reaction for aerobic respiration:
C₆H₁₂O₆ (glucose) + 6O₆ (molecule of oxygen) → 6CO₂ (carbon-dioxide) + 6H₂O (water).
Reaction shows that one molecule of glucose react with six molecules of oxygen.
Aerobic respiration<span> requires </span>oxygen<span> to create energy.</span>
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Phosphoglucoisomerase interconverts glucose 6‑phosphate to, and from, glucose 1‑phosphate. glucose 6 - phosphate phosphoglucoiso
vodomira [7]

<u>Answer:</u> The equilibrium constant of the reaction is 0.0526 and standard Gibbs free energy of the reaction is -7.296 kJ/mol

<u>Explanation:</u>

For the given chemical equation:

\text{Glucose-6-phosphate}\rightleftharpoons \text{Glucose-1-phosphate}

The expression of K_{eq} for above equation follows:

K_{eq}=\frac{[\text{Glucose-1-phosphate}]}{[\text{Glucose-6-phosphate}]}

We are given:

[\text{Glucose-1-phosphate}]=0.01M

[\text{Glucose-6-phosphate}]=0.19M

Putting values in above expression, we get:

K_{eq}=\frac{0.01}{0.19}=0.0526

The equation used to calculate standard Gibbs free energy of the reaction follows:

\Delta G^o=+RT\ln K_{eq}

where,

\Delta G^o = Standard Gibbs free energy

R = Gas constant = 8.314 J/K mol

T = Temperature = 25^oC=[25+273]K=298K

K_{eq} = Equilibrium constant of the reaction = 0.0526

Putting values in above equation, we get:

\Delta G^o=8.314J/K.mol\times 298K\times \ln (0.0526)\\\\\Delta G^o=-7296.5J/mol=7.296kJ/mol

Hence, the equilibrium constant of the reaction is 0.0526 and standard Gibbs free energy of the reaction is -7.296 kJ/mol

3 0
3 years ago
HELP PLEASE ASAP I need a good explanation
Lerok [7]

Answer:

B

Explanation:

Hellium is a gas...

Solids are particles that are packed together

liquids are particles that are together but conforme to their container

gas have space between them and conform to their holder

6 0
2 years ago
A buffer is prepared by dissolving 0.80 moles of NH3 and 0.80 moles of NH4Cl in 1.00 L of aqueous solution. If 0.10 mol of NaOH
Vikki [24]

Answer:

a. 10.54

Explanation:

reaction is

NH₃ +  NaOH   -----------------NH₄Cl + H₂O

0.10 mol NaOH will consume 0.10 mol NH₃ thereby decreasing the initial amount of moles NH₃ and increasing that of NH₄Cl

mol NH₃  = 0.80 - 010 = .70

mol NH₄Cl = 0.80 + .10 = 0.90

pH = pKₐ + log (( NH₃/NH₄Cl))

pH =  9.26 + log (( 0.90 + 0.70)) = 9.26 + 0.11 = 10.54

7 0
2 years ago
Elements are organized into groups / families according to their physical and chemical properties. Identify the elements that's
Kryger [21]

Answer:

1 valence - Alkali Metals: Li Lithium, Na Sodium, K Potassium

2 valence - Alkaline Earth Metals: Be Beryllium, Mg Magnesium, Ca Calcium

3 valence - Non-metals: B Boron, Al Aluminium

4 valence - Non-metals: C Carbon, Si Silicon

5 valence - Non-metals: N Nitrogen, P Phosphorus

6 valence - Non-metals: O Oxygen, S Sulfur, Se Selenium

7 valence - Halogens: F Fluorine, Cl Chlorine, Br Bromine

8 valence - Noble Gases: He Helium, Ne Neon, Ar Argon

3 0
3 years ago
Calculate the root means square velocity of nitrogen molecules in 25 degrees Celsius
Mademuasel [1]
Calculate the root mean square velocity of nitrogen molecules at 25°C.
297 m/s
149 m/s
515 m/s
729 m/s
7 0
3 years ago
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