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kolezko [41]
4 years ago
10

The complete oxidation of glucose (c6h12o6) to carbon dioxide and water in aerobic respiration consumes how many molecules of ox

ygen (o2)?
Chemistry
1 answer:
Butoxors [25]4 years ago
6 0
Answer is: 6 molecules of oxygen.
First, write down reaction for aerobic respiration:
C₆H₁₂O₆ (glucose) + 6O₆ (molecule of oxygen) → 6CO₂ (carbon-dioxide) + 6H₂O (water).
Reaction shows that one molecule of glucose react with six molecules of oxygen.
Aerobic respiration<span> requires </span>oxygen<span> to create energy.</span>
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Answer:

0.1 M

<h3>Explanation:</h3>
  • Molarity refers to the concentration of a solution in moles per liter.
  • It is calculated by dividing the number of moles of solute by the volume of solvent;
  • Molarity = Moles of the solute ÷ Volume of the solvent

<u>In this case, we are given;</u>

  • Number of moles of the solute, NH₄Cl as 0.42 moles
  • Volume of the solvent, water as 4200 mL or 4.2 L

Therefore;

Molarity = 0.42 moles ÷ 4.2 L

            = 0.1 mol/L or 0.1 M

Thus, the molarity of the solution will be 0.1 M

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