All categories

2 years ago

A lead apron is a ________________ instrument classification of disease transmission. Fill in the blank

Chemistry

1 answer:

pochemuha2 years ago

7 0

Answer:

A lead apron is a <u>non-critical </u> instrument.

Hope it helps!

You might be interested in

Calculate the equilibrium constant at 25 ∘C for the reaction Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

Murrr4er [49]

Answer:

1.7 × 10 ^42

Explanation:

Using Nernst equation

E°cell = RT/nF Inq

at equilibrium

Q=K

E°cell = 0.0257 /n Ink= 0.0592/n log K

Fe2+(aq)+2e−→Fe(s) E∘= −0.45 V

Ag+aq)+e−→Ag(s) E∘= 0.80 V

Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

balance the reaction

Fe → Fe²⁺ + 2e⁻ reversing for oxidation E° = 0.45 v

2 Ag⁺ +2e⁻ → 2Ag

n = 2 moles and K = equilibrium constant

E° cell = 0.80 + 0.45 = 1.25 V

E° cell = (0.0592 / n) log K

substitute the value into the equations and solve for K

(1.25 × 2) / 0.0592 = log K

42.23 = log K

k = 10^ 42.23

K = 1.7 × 10 ^42

8 0

3 years ago

When a -COOH group replaces a hydrogen in a hydrocarbon the result is a/an ____.

jonny [76]

Carboxylic acid...........

7 0

3 years ago

If I have a 50.0 liter container that holds 45 moles of gas at a

Darina [25.2K]

V= 50. L n=45 mol T= 200°C = 473k P=?

CP)X 50.L)= (45 mol)(0.0821 light_kimol)(473k)

P = 30am or 4000 kPa

5 0

4 years ago

What is the ph of a buffer prepared by adding 1.00 l of 1.0 m hcℓ to 750 ml of 1.5 m nahcoo? ka = 1.7 x 10-4?

alexandr1967 [171]

Ph = 2.837 ( solution is attached )

5 0

3 years ago

The initial pressure of a mixture of C6H6 and an excess of H2 in a rigid vessel is 1.21 atm. A catalyst is introduced. After the

KengaRu [80]

Answer:

mole fraction of C6H6 = 0.613 atm

Explanation:

The equation for this reaction is :

$C_6H_6 _{(g)} + 3H_2_{(g)} \to C_6H_{12}_{(g)}$

Initial P₁ P₂ 0

Final 0 P₂ -P₁/2 P₁

After completion of the reaction;

P₁ + P₂ = 1.21 atm ----- (1)

P₂ - P₁/2 + P₁ = 0.839 atm

P₂ + P₁/2 = 0.839 atm ----- (2)

Subtracting (2) from (1); we have:

P₁/2 = 0.371

P₁ = 0.742 atm

From(1)

P₁ + P₂ = 1.21 atm

0.742 atm + P₂ = 1.21 atm

P₂ = 1.21 atm - 0.742 atm

P₂ = 0.468 atm

Thus, the partial pressure of C6H6 = 0.742 atm

∴

Partial pressure = Total pressure × mole fraction of C6H6

mole fraction of C6H6 = Partial pressure / Total pressure

mole fraction of C6H6 = 0.742 atm / 1.21 atm

mole fraction of C6H6 = 0.613 atm

5 0

3 years ago