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VikaD [51]
2 years ago
11

Compare and contrast atoms elements compounds and molecules

Chemistry
1 answer:
N76 [4]2 years ago
6 0

atoms = smallest unit of an element

elements = contain only one type of atom

compounds = two or more elements that are chemically bound together

molecules = a group of atoms bonded together

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iren2701 [21]

Answer:

reaction, reversed, The Law Of Conservation of Mass, mass, rusts, oxygen

Explanation:

HOPE THIS HELPS!

4 0
2 years ago
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At higher temperatures,
valentinak56 [21]

Answer:

reaction rates increase because reactants move faster, collide more often, and produce more collisions with the required energy of activation.

Explanation:

<em>A</em><em>t</em><em> </em><em>h</em><em>i</em><em>g</em><em>h</em><em>e</em><em>r</em><em> </em><em>t</em><em>e</em><em>m</em><em>p</em><em>e</em><em>r</em><em>a</em><em>t</em><em>u</em><em>r</em><em>e</em><em>s</em><em>,</em><em> </em>the reactant atoms gain high kinetic energy which decreases the intermolecular forces of attraction between these atoms/molecules.

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3 0
3 years ago
Find the mass in kilograms of the liquid air that is required to produce 600L of oxygen. In normal condition, 1L of liquid air h
IgorC [24]

Mass in kilograms of liquid air required = 0.78 kg

<u>Given that </u>

1 Litre of liquid air contains 1.3 grams of oxygen ( air )

<u />

<u> Determine the a</u><u>mount of liquid air</u><u> in Kg</u>

volume of air given = 600 L

mass of liquid air required = x

1 litre = 1.3 grams

600 L =  x

∴ x ( mass of liquid air ) = 1.3 * 600

                                       = 780 g  = 0.78 kg

Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg

Learn more about liquid air : brainly.com/question/636295

3 0
2 years ago
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xxMikexx [17]

Answer:

answer-

The relative atomic mass = 204.4

explanation:

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Therefore ,

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relative mass of thallium = 204.40 amu

Thus,

relative atomic mass of thalium =204.4 ( to 1 decimal place)

6 0
3 years ago
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stich3 [128]

a) cross out 11mL from list 1, 2 mL from list 2, and 998 cm3 from list 3.

b) circle 200 mL from list 1, 801 mL from list 2, and 1 L from list 3.

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