Answer:
A=202
Step-by-step explanation:
A=2(wl+hl+hw)
2·(13·5+2·5+2·13)=202
When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
The answer is 12!
Hope this helps! :D
------The answers got taken down :(------
First combine like terms so
2x+6=3x-8
3x - 2x =1X
-6 - -8= -14
1X ÷ -14
then just divide
