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Helen [10]
3 years ago
11

Some people must eat a low-sodium diet with no more than 2,000 mg of sodium per day. By eating 1 cracker, 1 pretzel, and 1 cooki

e, a person would ingest 149 mg of sodium. If a person ate 8 pretzels and 8 cookies, he or she would ingest 936 mg of sodium. By eating 6 crackers and 7 pretzels, the person would take in 535 mg of sodium. Find the amount of sodium in each.
Chemistry
1 answer:
Leni [432]3 years ago
6 0

Answer:

The amount of sodium is 32 mg per cracker, 49 mg per pretzel and 68 mg per cookie.

Explanation:

Let's assume amount of sodium is x mg per cracker, y mg per pretzel and z mg per cookie.

So, the following three equations can be written as per given information:

x+y+z = 149 ........(1)

8y+8z = 936 ........(2)

6x+7y = 535 .........(3)

From equation- (2), y+z = \frac{936}{8} = 117

By substituting the value of (y+z) in equation- (1) we get,

                          x = 149-(y+z) = 149-117 = 32

By substituting the value of x into equation- (3) we get,

                           y = \frac{535-(6\times 32)}{7} = 49

By substituting the value of y  into equation- (2) we get,

                           z = (117-49) = 68

So, the amount of sodium is 32 mg per cracker, 49 mg per pretzel and 68 mg per cookie.

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Hence the compound with similar interaction can dissolve in diethyl  ether .

Here , MgBr2  is an ionic compound . there is ion-ion interactions occurs which is not similar to dipole -dipole interaction in diethyl ether .hence the solubility of MgBr2 in diethyl ether is less .

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How many grams of water can be produced from 4.6 grams of Hydrogen and 7.3 grams of Oxygen?
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Answer:

The answer to your question is 8.21 g of H₂O

Explanation:

Data

mas of water = ?

mass of hydrogen = 4.6 g

mass of oxygen = 7.3 g

Balanced chemical reaction

                   2H₂  +  O₂  ⇒   2H₂O

Process

1.- Calculate the atomic mass of the reactants

Hydrogen = 4 x 1 = 4 g

Oxygen = 16 x 2 = 32 g

2.- Calculate the limiting reactant

Theoretical yield = H₂/O₂ = 4 / 32 = 0.125

Experimental yield = H₂/ O₂ = 4.6/7.3 = 0.630

From the results, we conclude that the limiting reactant is Oxygen because the experimental yield was higher than the theoretical yield.

3.- Calculate the mass of water

                   32 g of O₂ ---------------- 36 g of water

                   7.3 g of O₂ ---------------   x

                          x = (7.3 x 36) / 32

                          x = 262.8 / 32

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. 125g of water has an initial temperature of 25.6°C, and is heated by 50.0g of a metal
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Answer : The specific heat of the metal is, 0.451J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

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T_f = final temperature of mixture = 29.3^oC

T_1 = initial temperature of metal = 115.0^oC

T_2 = initial temperature of water = 25.6^oC

Now put all the given values in the above formula, we get

(50.0g)\times c_1\times (29.3-115.0)^oC=-[(125g)\times 4.18J/g^oC\times (29.3-25.6)^oC]

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