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3 years ago

How to test a hypothesis using scientific inquiry?

Chemistry

1 answer:

IrinaK [193]3 years ago

5 0

Answer:The most common way to test a hypothesis is to create an experiment.

Explanation:

The scientific method has 5 steps, plus one feedback step:

1 Make an observation.

2 Ask a question.

3 Form a hypothesis, or testable explanation.

4 Make a prediction based on the hypothesis.

5 Test the prediction.

6 Iterate: use the results to make new hypotheses or predictions.

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What is the mass, in grams, of a sample of 6.98 × 1024 atoms of magnesium (Mg)?

monitta

N=6.98*10²⁴
Nₐ=6.022*10²³ mol⁻¹

n(Mg)=N/Nₐ

m(Mg)=n(Mg)M(Mg)=M(Mg)N/Nₐ

m(Mg)=24.3g/mol*6.98*10²⁴/(6.022*10²³mol⁻¹)=281.7 g

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3 years ago

At top, Image 1 shows 2 C's connected by 2 lines. Each C is connected by single lines to 2 H's. At bottom, two dots and 12 C's i

Nana76 [90]

Answer: c

Explanation: Trust me

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3 years ago

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How is hydrogen different from alkali metals?

Irina18 [472]

Hydrogen is different from alkali metals because it also exhibits the properties of inert gas

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3 years ago

In which orbitals would the valence electrons for selenium (Se) be placed?

RSB [31]

Selenium falls in the same column with oxygen therefore it has the same number of valence electrons with oxygen which is 6. It fills the 3d orbital but only 4s and 4p are counted. The electronic configuration is [Ar]3d^10 4s^2.

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3 years ago

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If 9.5 × 10²⁵ molecules of CO₂ are produced in a combustion reaction, what is the mass in kg of CO₂ that is produced?

Leno4ka [110]

Answer:

6.9428 kg of CO2

Explanation:

1) Use Avogadro's number that states 1 mole = 6.022 x 10^23 particles. Convert 9.5 x 10^25 molecules into moles.

9.5 x 10^25 CO2 molecules $x\frac{1 mole CO2}{6.022 x 10^23}$ = 157.75 moles CO2

2) Convert 157.75 moles of CO2 into grams. CO2's molar mass is 44.01g.

$157.75moles CO2$ $x \frac{44.01g/mol}{1 mole CO2}$ = 6942.79g

3) Convert 6942.79 grams into kilograms (divide by 1000):

6.9428 kg

4 0

3 years ago