Answer:
The sun would appear to move more slowly across Mercury's sky.
Explanation:
This is because, the time it takes to do one spin or revolution on Mercury is 176 days (which is its period), whereas, the time it takes to do one spin or revolution on the Earth is 1 day.
Since the angular speed ω = 2π/T where T = period
So on Mercury, T' = 176days = 176 days × 24 hr/day × 60 min/hr × 60 s/min = 15,206,400 s
So, ω' = 2π/T'
= 2π/15,206,400 s
= 4.132 × 10⁻⁷ rad/s
So on Earth, T" = 1 day = 1 day × 24 hr/day × 60 min/hr × 60 s/min = 86,400 s
So, ω" = 2π/T"
= 2π/86,400 s
= 7.272 × 10⁻⁵ rad/s
Since ω' = 4.132 × 10⁻⁷ rad/s << ω" = 7.272 × 10⁻⁵ rad/s, <u>the sun would appear to move more slowly across Mercury's sky.</u>
Answer:
there are literally millions - alkanes, alkenes, alkynes, alcohols, esters, carboxylic acids... to name but a few.
Explanation:
Answer:
By taking away research funds if certain standards ar not met
Explanation:
<span>Solubility product constant (Ksp) is </span>applied to the saturated ionic solutions<span> which are in equilibrium with its
solid form. The solid is partially dissociated into its ions.</span><span>
For the BaF, the dissociation as follows;
BaF</span>₂(s) ⇄ Ba²⁺(aq)
+ 2F⁻(aq)
<span>
Hence,
Ksp = [Ba</span>²⁺(aq)] [F⁻(aq)]²
Answer:
<u>The new pressure is 1.0533 atm</u>
<u></u>
Explanation:
According to<u> Boyle's Law :</u> The Pressure of fixed amount of gas is inversely proportional to Volume at constant temperature.
PV = Constant
P1V1 = P2V2
.....(1)
P1 = 3.16 atm
Accprding to question ,
V1 = V
V2 = 3 V
Insert the value of V1 , V2 and P1 in the equation(1)
V and V cancel each other
