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4 years ago

Simplify 6x.h.x.2xm. please

Mathematics

1 answer:

mixas84 [53]4 years ago

6 0

7x . h . 2xm

You can put together 6x and x

but since h, and 2xm arent alike terms, you cant combine

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What value of m will make this expression equal to 0?

Svetllana [295]

Answer:

-2.25

Step-by-step explanation:

The only way the expression can equal zero is if the numerator is zero.

The numerator is the product of 5 and the expression m + 2.25

A product is equal to zero if one of the factors equals zero.

5 is obviously not equal to zero, so the only way the product of 5 and m + 2.25 can equal zero is if the factor m + 2.25 equals zero.

We set m + 2.25 equal to zero and solve for m.

m + 2.25 = 0

Subtract 2.25 from both sides.

m = -2.25

If you add -2.25 to 2.25, you get zero. Zero times 5 equals zero. That meakes the expression equal to zero.

Answer: -2.25

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3 years ago

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What is the perimeter of rhombus WXYZ?

oksian1 [2.3K]

<u>Answer</u>:

The perimeter of rhombus WXYZ is $4 \sqrt{13}$

<u>Step-by-step explanation:</u>

Step 1 :Finding length of XY

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =3

$y_1$ = -1

$y_2$ =2

XY = $\sqrt{(3-5)^2 +(2 -(-1))^2}$

XY = $\sqrt{(3-5)^2 +(2 +1))^2}$

XY = $\sqrt{(-2)^2 +(3))^2}$

XY = $\sqrt{4 +9}$

XY = $\sqrt{(13)}$

Step 2 :Finding length of YZ

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 3

$x_2$ =5

$y_1$ = 2

$y_2$ =5

YZ = $\sqrt{(5-3)^2 +(5-2)^2}$

YZ = $\sqrt{(2)^2 +(3)^2}$

YZ = $\sqrt{4 +9}$

YZ = $\sqrt{(13)}$

Step 3 : :Finding length of ZW

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =7

$y_1$ = 5

$y_2$ =2

ZW = $\sqrt{(7-5)^2 +(5-2)^2}$

ZW = $\sqrt{(2)^2 +(3)^2}$

ZW = $\sqrt{4 +9}$

ZW = $\sqrt{(13)}$

Step 4 :Finding length of WX

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 7

$x_2$ =5

$y_1$ = 2

$y_2$ = -1

WX = $\sqrt{(7-5)^2 +((-1)-2)^2}$

WX = $\sqrt{(2)^2 +(-3)^2}$

WX = $\sqrt{4 +9}$

WX = $\sqrt{(13)}$

Step 5: finding the perimeter of the rhombus

Perimeter= 4 X side

=> $4 \times \sqrt{13}$

=> $4 \sqrt{13}$

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Answer:

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kaheart [24]

= $\frac{1}{ 4^{3} }$
= $\frac{1}{64}$

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