Fv=p(1+0.0675/2)^2*16
Fv=p(1+0.0675/2)^32
Fv=5,033.22
m + 4mn – 9m1n + nm6 + 5 is a exprsssion with four terms
Using the normal distribution, it is found that 63.18% of the area under the curve of the standard normal distribution is between z = − 0.9 z = - 0.9.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The area within 0.9 standard deviations of the mean is the <u>p-value of Z = 0.9(0.8159) subtracted by the p-value of Z = -0.9(0.1841)</u>, hence:
0.8159 - 0.1841 = 0.6318 = 63.18%.
More can be learned about the normal distribution at brainly.com/question/4079902
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f(3) = 1
substitute x = 3 into f(x)
f(3) = (2 × 3) - 5 = 6 - 5 = 1
Answer:
v = 25.6
Step-by-step explanation:
1. Multiply both sides of the equation by 4.
(6.4)(4) = 25.6