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SIZIF [17.4K]
4 years ago
10

What percentage of a radioactive species would be found as daughter material after seven half–lives?

Chemistry
1 answer:
irinina [24]4 years ago
6 0
0.78  is what the verified answer says 
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i am thinking that they will be extinct

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What name is given to the family of elements that includes chlorine?
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halogens

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Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 9.00 moles of aluminum sulfate, al2(so4)3. express the nu
klasskru [66]
<span>Ans : The chemical formula for aluminum sulfate is Alâ‚‚(SOâ‚„)â‚ 6.00 mol Alâ‚‚(SOâ‚„)â‚ Al: 6.00 mol Alâ‚‚(SOâ‚„)â‚ x (2 mol Al / 1 mol Alâ‚‚(SOâ‚„)â‚ ) = 12.00 mol Al S: 6.00 mol Alâ‚‚(SOâ‚„)â‚ x (3 mol S / 1 mol Alâ‚‚(SOâ‚„)â‚ ) = 18.00 mol S O: 6.00 mol Alâ‚‚(SOâ‚„)â‚ x (12 mol O / 1 mol Alâ‚‚(SOâ‚„)â‚ ) = 72.00 mol O</span>
5 0
3 years ago
Which of the following could you do to increase the strength of an electromagnet?
notsponge [240]

Change the core from wood to iron. This is because iron is a magnetic material while wood is not magnetic hence cant acquire magnetism. Other factors that would increase the strength of electromagnet would be; increasing the amount of electric current, and increasing the number of winding's.

6 0
3 years ago
Write the balanced equation and determine the information requested in each of the following.
Elena L [17]

Answer:

See explanation.

Explanation:

Hello!

In this case, we can proceed as follows:

1. Here, the undergoing chemical reaction is:

C_2H_2+\frac{5}{2} O_2\rightarrow 2CO_2+H_2O

Thus, the moles and mass of water turn out:

n_{H_2O}=20.0kgC_2H_2*\frac{1000gC_2H_2}{1kgC_2H_2} *\frac{1molC_2H_2}{26.04gC_2H_2} *\frac{1molH_2O}{1molC_2H_2}=768molH_2O\\\\m_{H_2O}=768molH_2O*\frac{18.02gH_2O}{1molH_2O}=13,840 gH_2O

2. Here, the undergoing chemical reaction is:

CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2

So the required moles of HCl and the yielded of water are:

n_{CaCO_3}=2.6molHCl*\frac{1molCaCO_3}{2molHCl}=1.3molCaCO_3\\\\ n_{H_2O}=2.6molHCl*\frac{1molH_2O}{2molHCl}=1.3molH_2O

3. Here, the undergoing chemical reaction is:

Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O

Now, we apply each mole ratio obtain:

A.

n_{H_2SO_4}=2.6molAl_2O_3*\frac{3molH_2SO_4}{1molAl_2O_3} =7.8molH_2SO_4

B.

n_{Al_2(SO_4)_3}=2.6molAl_2O_3*\frac{1molAl_2(SO_4)_3}{1molAl_2O_3} =2.6molAl_2(SO_4)_3

Best regards!

4 0
3 years ago
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