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4 years ago

What percentage of a radioactive species would be found as daughter material after seven half–lives?

Chemistry

1 answer:

irinina [24]4 years ago

6 0

0.78 is what the verified answer says

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What is the volume of 5.8g of H2?

BartSMP [9]

At standard temperature and pressure, one mole of gas occupies 22.4 L. Knowing this, we must convert the grams to moles and moles to liters to get your answer. Here's how you do it!
$\frac{5.8gH2}{1} | \frac{1moleH2}{2.0gH2}| \frac{22.4LH2}{1moleH2} \\ \frac{5.8*1*22.4LH2}{2.0} \\ \frac{129.92LH2}{2.0} \\ 64.96LH2 \\ 65LH2$
With significant figures accounted for, 5.8 grams of hydrogen gas occupies 65 L.

Hope this helps!

4 0

4 years ago

38.2mm converted into cm

lina2011 [118]

38.mm converted into cm would be 3.82

5 0

3 years ago

Explain how scientist learned about the magnetic poles of the Earth.

MatroZZZ [7]

Answer:

They learned because they keeped studying they would never give up and if they found something new or interesting they may have just studied it more.

Explanation:

3 0

3 years ago

Read 2 more answers

PLSSSSS HELP I DONT GET THIS PROBLEMMMM

Aleks [24]

Answer:

C. 7370 joules.

Explanation:

There is a mistake in the statement. Correct form is described below:

<em>Using the above data table and graph, calculate the total energy in Joules required to raise the temperature of 15 grams of ice at -5.00 °C to water at 35 °C. </em>

The total energy needed to raise the temperature is the combination of latent and sensible heats, all measured in joules, and represented by the following model:

$Q = m\cdot [c_{i} \cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})]$ (1)

Where:

$m$ - Mass of the sample, in grams.

$c_{i}$ - Specific heat of ice, in joules per gram-degree Celsius.

$c_{w}$ - Specific heat of water, in joules per gram-degree Celsius.

$L_{f}$ - Latent heat of fusion, in joules per gram.

$T_{1}$ - Initial temperature of the sample, in degrees Celsius.

$T_{2}$ - Melting point of water, in degrees Celsius.

$T_{3}$ - Final temperature of water, in degrees Celsius.

$Q$ - Total energy, in joules.

If we know that $m = 15\,g$ , $c_{i} = 2.06\,\frac{J}{g\cdot ^{\circ}C}$ , $c_{w} = 4.184\,\frac{J}{g\cdot ^{\circ}C}$ , $L_{f} = 334.72\,\frac{J}{g}$ , $T_{1} = -5\,^{\circ}C$ , $T_{2} = 0\,^{\circ}C$ and $T_{3} = 35\,^{\circ}C$ , then the final energy to raise the temperature of the sample is:

$Q = (15\,g)\cdot \left[\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (5\,^{\circ}C)+ 334.72\,\frac{J}{g} + \left(4.184\,\frac{J}{g\cdot ^{\circ}C}\right)\cdot (35\,^{\circ}C) \right]$

$Q = 7371.9\,J$

Hence, the correct answer is C.

8 0

3 years ago

What is associated with an object that has gravitational potential energy

Molodets [167]

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.

8 0

3 years ago