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GarryVolchara [31]
3 years ago
12

If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w

e know there were 11 grams of Oxygen on the reactants side of the equation? (answer with only a number)
Chemistry
1 answer:
Nata [24]3 years ago
4 0

4.1g

Explanation:

Given parameters:

Mass of carbon dioxide = 15g

Mass of oxygen gas = 11g

Unknown:

Mass of carbon consumed = ?

Solution:

   Equation of the reaction:

                                              C +  O₂   →   CO₂

    To solve this problem from the balanced equation,  we have to use the amount of product formed and work to Carbon. This is because, we are sure of the amount of carbon dioxide formed but the amount of the given oxygen gas used is not precise.

  Number of moles of CO₂ = \frac{mass}{molar mass}

Molar mass of CO₂ = 12 + (16 x2) = 44g/mol

   Number of moles of CO₂ = \frac{15}{44} = 0.34mole

From the equation of the reaction;

              1 mole of CO₂  is produced from 1 mole of C

           0.34mole of CO₂  will produce 0.34mole of C

Mass of carbon reacting = number of moles x molar mass = 0.34 x 12 = 4.1g

Learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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A student has a mixture of salt (NaCl) and sugar (C12H22O11). To determine the percentage, the student measures out 5.84 grams o
julsineya [31]

Answer:

The volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml

Explanation:

Here we have the reaction of AgNO₃ and NaCl as follows;

AgNO₃(aq) + NaCl(aq)→ AgCl(s) + NaNO₃(aq)

Therefore, one mole of silver nitrate, AgNO₃, reacts with one mole of sodium chloride, NaCl, to produce one mole of silver choride, AgCl, and one mole of sodium nitrate, NaNO₃,

Therefore, since 5.84 grams of NaCl which is 58.44 g/mol, contains

Number \, of \, moles, n  = \frac{Mass}{Molar \ mass} =  \frac{5.84}{58.44} = 0.09993 \ moles \ of \ NaCl

0.09993 moles of NaCl will react with 0.09993 moles of AgNO₃

Also, as 1.0 M solution of AgNO₃ contains 1 mole per 1 liter or 1000 mL, therefore, the volume of AgNO₃ that will contain 0.09993 moles is given as follows;

0.09993 × 1 Liter/mole= 0.09993 L = 99.93 mL

Therefore, the volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml.

3 0
3 years ago
The diagram below shows the branching tree diagram for humans. The text box below it shows the set of derived shared characteris
pentagon [3]

Answer:

I would write "terrestrial/lives on land during all life stages" between the frog and pigeon branches

Explanation:

Jaw evolution has started with fish, so i'd place that before the perch, evolution of four limbs is next and I would plate it between the perch and the frog. Evolution of an egg has ensured that organisms remain terrestrial during all stages of life and don't need to rely on water to lay their eggs. So I would place that between the frog and the pigeon. True mammary glands and true hair, as we know it formed on mammals so i'd place that between the pigeon and the rats (although synapsids evolved similar structures long before birds even existed). And lastly, I would place "walking on two legs" between rats and human branches. Because our ancestors evolved bipedalism relatively late.

6 0
2 years ago
Which term names the concentration of salts dissolved in a liquid?
Viefleur [7K]
Hey there!
The answer is D, Salinity.
Salinity is the concentration of salt in water. Ocean water often has high salinity and this can contribute to things like upwelling and water density- but these all start from salinity.
Hope this helps!
4 0
3 years ago
Read 2 more answers
During region C of the graph above the energy being absorbed is a. increasing the velocity of the water particles. b. increasing
Mkey [24]

Answer:

Your answer would be B. Increasing the distance between the water molecules and increasing their phase energy.

Explanation:

Hope this helps you answer this question!

7 0
2 years ago
Calculate in gramm the mass of 0.1 mole of hydrochloric acid(h=1 ,cl=35.5)​
babunello [35]

Answer:

mass of HCl = 3.65 g

Explanation:

Data Given:

Moles of hydrochloric acid HCl = 0.1 mole

Mass in grams of hydrochloric acid HCl = ?

Solution:

Mole Formula

                  no. of moles = Mass in grams / molar mass

To find Mass in grams rearrange the above Formula

                Mass in grams = no. of moles x molar mass . . . . . . . (1)

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Put values in equation 1

              Mass in grams = 0.1 mole x 36.5 g/mol

              Mass in grams = 3.65 g

mass of HCl = 3.65 g

6 0
2 years ago
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