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2 years ago

Which of the following would result in the magnesium ribbon 'dissappearing' in less than 45 seconds?

Chemistry

2 answers:

zheka24 [161]2 years ago

4 0

Answer:

your should probably be warming the acid

Explanation:

because when you are it is disappearing

lana66690 [7]2 years ago

3 0

Answer:

Warming the acid

Explanation:

This is because when the acid is heated, the particle of the acid gain more energy (kinetic to be more precise) causing more collisions to occur, colliding even more with the particles of the magnesium ribbon. This increases the rate of disappearance of the magnesium ribbon.

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3 years ago

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2 years ago

A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0

3 years ago

LAB: predicting products

kondor19780726 [428]

Answer:

1) synthesis MgI2

2) double replacement CuS + (HCl)2

3) double replacement, not sure ab the formula sorry

4 0

2 years ago

What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?

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PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm

6 0

3 years ago