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2 years ago

Which of these is a mixture of particles that are large enough to scatter or block light

Chemistry

1 answer:

Daniel [21]2 years ago

5 0

The answer is C. because <span>particles settle out over time ,can block light and scatter light .</span>

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10. If 3.5 kJ of energy are added to a 28.2 g sample of iron at 20°C, what

igor_vitrenko [27]

Answer:

569K

Explanation:

Q = 3.5kJ = 3500J

mass = 28.2g

∅1 = 20°C = 20 + 273 = 293K

∅2 = x

c = 0.449

Q = mc∆∅

3500 = 28.2×0.449×∆∅

3500 = 12.6618×∆∅

∆∅ = 3500/12.6618

∆∅ = 276.4220

∅2 - ∅1 = 276.4220

∅2 = 276.4220 + ∅1

∅2 = 276.4220 + 293

∅2 = 569.4220K

∅2 = 569K

3 0

2 years ago

How many moles of Al would be produced from 20 moles of Al2O3?<br> 2Al2O3<br> -><br> 4A1 + 302

Evgesh-ka [11]

<h3>Answer:</h3>

$\displaystyle 40 \ mol \ Al$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 40 \ mol \ Al$

<u>Step 4:Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

4 0

2 years ago

You have been shipwrecked on a deserted island with no running water/fresh water, you have your clothes and a plastic bag contai

artcher [175]

Answer:

i have no clue

Explanation:

6 0

2 years ago

photosynthesis in plants require chloroplasts and light energy. identify two materials plants also use in this process

Nataliya [291]

I would assume carbon and water if not Im sorry.

5 0

3 years ago

. The ring shape of the Cartwheel Galaxy is due to:

dlinn [17]

The ring shape of the Cartwheel Galaxy is due to collisions with another galaxy.

<h3>What causes the ring shape of the Cartwheel Galaxy?</h3>

The unusual shape of the Cartwheel Galaxy is due to a collision with a smaller galaxy. The recent star burst has lighted up the Cartwheel rim which has a diameter larger than that of the Milky Way galaxy in which our planet exists. The Cartwheel Galaxy is a lenticular ring galaxy which is about 500 million light-years away. This galaxy was discovered by Fritz Zwicky in the year 1941.

So we can conclude that the ring shape of the Cartwheel Galaxy is due to collisions with another galaxy.

Learn more about galaxy here: brainly.com/question/13956361

#SPJ1

7 0

1 year ago