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Karo-lina-s [1.5K]
3 years ago
10

Hector paints a picture which is 10 inches longer than it is wide. When he frames it, the outside dimensions (that is the length

and the width) are each two inches longer. If the area of the picture with the frame is 40 sq inches more than the area of the picture without its frame, what is the length of the original painting?
Mathematics
1 answer:
Step2247 [10]3 years ago
8 0
X * (x + 10) = y - 40
(x + 2)(x + 12) = y
x^2 + 10x = x^2 + 14x + 24 - 40
10x = 14x - 16
-4x = -16
x = 4
4 + 10 = 14
The length of the original painting is 14 inches long.
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Step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

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3 years ago
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Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the conversion rate for both banks is not given.

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For Bank B:

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Answer:

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