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Karo-lina-s [1.5K]
3 years ago
10

Hector paints a picture which is 10 inches longer than it is wide. When he frames it, the outside dimensions (that is the length

and the width) are each two inches longer. If the area of the picture with the frame is 40 sq inches more than the area of the picture without its frame, what is the length of the original painting?
Mathematics
1 answer:
Step2247 [10]3 years ago
8 0
X * (x + 10) = y - 40
(x + 2)(x + 12) = y
x^2 + 10x = x^2 + 14x + 24 - 40
10x = 14x - 16
-4x = -16
x = 4
4 + 10 = 14
The length of the original painting is 14 inches long.
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Answer:

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4x -8 > 24-2x

Add 2x to each side:

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8 0
3 years ago
mean of 164,175,178,166,167,145,176,150,174,162,180,156,173,158,182,184,160,172,186,168,195,169,171,187,170
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that is,

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Hi there

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================================================

Work Shown:

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3 years ago
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