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Katarina [22]
3 years ago
10

What is the kinetic theory of matter? How does it relate to the motion of molecules?

Physics
1 answer:
navik [9.2K]3 years ago
3 0
The Kinetic<span> Molecular </span>Theory<span> explains the forces between </span>molecules<span> and the energy that </span>they<span> possess.

</span>
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A molecule of roughly spherical shape has a mass of 6.10 × 10-25 kg and a diameter of 0.70 nm. The uncertainty in the measured p
Ilia_Sergeevich [38]

Answer:

\Delta v = 0.123 m/s

Explanation:

As per the law of uncertainty we know that

\Delta p \times \Delta x = \frac{h}{4\pi}

now we know that

\Delta x = 0.70 nm

m = 6.10 \times 10^{-25}

also we have

h = 6.626 \times 10^{-34} J.s

now we will have

m\Delta v \times \Delta x = \frac{h}{4\pi}

(6.10 \times 10^{-25})\Delta v \times (0.70 \times 10^{-9}) = \frac{6.626 \times 10^{-34}}{4\pi}

\Delta v= 0.123 m/s

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3 years ago
cell membranes contain channels that allow K + ions to leak out consider channel that has diameter of nm and length of nm if cha
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Answer:

Resistivity (rho) = Resistance (G) * Area (\pi r^2) / Length (nm)

Explanation:

if rho is the resistivity, then according to the proper equation re-arrangement the resistance is G. Then, Area can be calculated by radius and dividing their product by the length of channel.

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3 years ago
5. The ends of a 10 cm laser rod, index of refraction = 1.76, has its ends coated for reflectivity of 99.9 % and 90 %. If there
Jobisdone [24]

Answer:

the fractional loss per pass =0.053

the decay time of the cavity =11 ns

Explanation:

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the fractional loss per pass= \alpha l - ln(R_1R_2)^ \frac {1}{2}

but no excited state absorption, therefore \alpha is 0

= - ln(R_1R_2)^ \frac {1}{2}\\\\=- ln(0.999* 0.9)^ \frac {1}{2}

=0.053

b) the decay time of the cavity:

T_c = \frac{nd}{cl_f}=\frac{1,76 * 10 *10^-2}{3 *10^8 *0.53}

=1.1 *10^-8 seconds

=11 ns

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Paleontology is the scientific study of life that existed prior to
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3 years ago
1. Part A
Reika [66]

Answer:

B. 2. A baseball was hit by a bat and now flying through the air.

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