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3 years ago

What shape is the orbit of the planets

Physics

2 answers:

makkiz [27]3 years ago

8 0

C: Spheres because it orbits arounds

Sergio [31]3 years ago

5 0

The shapes of the planetary orbits are all slightly slightly slightly eccentric
ellipses. If you saw a drawing of the orbit of any planet on paper, you
couldn't tell the difference from a perfect circle.

Most COMETs, on the other hand, have very squashed, greatly elongated
orbits. When they're out, they go way way out, and when they're in, they
can be closer to the Sun than Mercury is.

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The mass of an object changes as the distance from the center of gravity changes.

Alchen [17]

Answer:

true

Explanation:

this is the answer to this question

8 0

3 years ago

Calculate the electric field associated to an electric dipole for two charges separated 10-8 m with a dipole moment of 10-33 C m

Alex Ar [27]

Answer:

18 N/C

Explanation:

Given that:

Electric field constant, k = 9*10^9 N/c

Distance, r = 10^-8 m

Dipole moment, p = 10^-33

Using the relation for electric field due to dipole :

E = [2KP / r³]

E = (2 * (9*10^9) * 10^-33) ÷ (10^-8)^3

E = (18 * 10^9 * 10^-33) ÷ 10^-24

E = [18 * 10^(9-33)] ÷ 10^-24

E = (18 * 10^-24) / 10^-24

E = 18 * 10^-24+24

E = 18 * 10^0

E = 18 N/C

5 0

3 years ago

A grindstone of mass 12 kg and radius 0.3 m is initially rotating freely at 48 rad/sec. An axe is brought into contact with the

lesya [120]

Answer:

$I = 0.54\,kg\cdot m^{2}$

Explanation:

1) The moment of inertia of the grindstone is:

$I = \frac{1}{2}\cdot m \cdot r^{2}$

$I = \frac{1}{2}\cdot (12\,kg)\cdot (0.3\,m)^{2}$

$I = 0.54\,kg\cdot m^{2}$

4 0

4 years ago

Read 2 more answers

convert watts to hpThe headlights of a moving car draw about 9 A from the 12 V alternator, which is driven by the engine. Assume

iVinArrow [24]

Answer: 0.17hp

Explanation:

Power output = power input × 85%

Power output = power input × 0.85

Power input = IV/0.85

Power input = 9×12/0.85

Power input = 108/0.85

= 127.058 watts

Converting to horse power = 127.058W × 1horse power/745.7W

= 127.058 × 0.001341

= 0.17hp

4 0

3 years ago

In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 Hz passes through a pair of slits separated by 2.20 × 1

Lyrx [107]

Answer:

$\theta=4.64^{\circ}$

Explanation:

It is given that,

The frequency of monochromatic light, $f=5\times 10^{14}\ Hz$

Slit separation, $d=2.2\times 10^{-5}\ m$

Let $\theta$ is the angle away from the central bright spot the third bright fringe past the central bright spot occur. The condition for bright fringe is :