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notsponge [240]
3 years ago
6

Which is the following is a modern method used to pressure food

Physics
1 answer:
rosijanka [135]3 years ago
8 0

Answer:

1. Spray Drying

Explanation:

it is the most modern

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Which situation illustrates Newton's first law?
Ne4ueva [31]
Newton's first law states that - An object in motion will stay in motion unless compelled to change it's state by the action of an external force.

Thus, your answer is D.
7 0
4 years ago
water is boiling in a pan at 100c if heat is transferred to the pan at a rate of 2 kw how much water in kg will evaporate in 10m
Ksju [112]

Answer:

The mass of water that will evaporate 2.857 kg.

Explanation:

Given;

temperature of the water, T = 100 c

rate of heat transfer,  H = 2 kW = 2000 w

time, t = 10 min = 10 min x 60s = 600s

heat capacity of water is given by;

Q = McΔT

Where;

Q is the quantity of heat transfer to the pan = P x t =  2000 x 600 = 1200000 J.

c is specific heat capacity of water = 4200 J/kg.°C

m = (Q) / (cΔT)

m = (1200000) (4200 x 100)

m = 2.857 kg

Therefore, the mass of water that will evaporate 2.857 kg.

6 0
3 years ago
Why is Venus sometimes called Earth’s twin?
monitta

Answer:

B.

Venus is the same size and density.

Explanation:

It is becuase venus has the same size and density as earth

8 0
3 years ago
Read 2 more answers
Is the Florida scrub a forest or grassland
PIT_PIT [208]
It is a forest. Hope this helps. Much luck
4 0
3 years ago
A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio
Gnesinka [82]

Answer:

a).a_p=-2.39x10^{-12} rad/s^2

b).t=1016298.8 years

c).T_i=80.58x10^{-3}s

Explanation:

a).

The acceleration for definition is the derive of the velocity so:

a_p=\frac{dw}{dt}

w=\frac{2\pi}{t}

a_p=\frac{dw}{dt}=-\frac{2\pi}{t^2}*\frac{dT}{dt}

dT=0.0808s

dt=1 year*\frac{365d}{1year} \frac{24hr}{1d} \frac{60minute}{1hr} \frac{60s}{1minute}=31.536x10^{6}s

Replacing

a_p=-\frac{2\pi}{0.082s^2}*\frac{9.84x10^{-7}}{31.536x10^{6}s}= -2.39x10^{-12} rad/s^2

b).

If the pulsar will continue to decelerate at this rate, it will  stop rotating at time:

t=\frac{w}{a_p}

w=\frac{2\pi }{t}=\frac{2\pi }{0.0820s}=76.62 rad/s

t=\frac{76.62 rad/s}{2.39x10^{-12}rad/s^2}= 3.2058x10^{13}s

t=1016298.8 years

c).

582 years ago to 2019

1437

T_i=0.0820-9.84x10^{-7}*1437)=80.58x10^{-3}s

5 0
4 years ago
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