Question

A ball of mass 2kg falls from a height of 200m. Calculate it's kinetic energy after falling a distance of 50m . (g=10m/s²) . Neglect air resistance.

Answer 1

Answer:

U = 1000 J

Explanation:

By the conservation of energy, potential energy is converted into kinetic energy when the ball falls from a height.

 $U = \frac{1}{2} mv^2 = mgh$

U = Energy (in Joules)

m = mass (in kg)

v = velocity in (m/s)

g = acceleration due to gravity (in m/s^2)

h = height (in m)

Let's use $mgh$ as we have the values given.

$U = 2(10)(50)$

$U = 1000 J$