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Murrr4er [49]
3 years ago
12

Which of the following is a characteristic of alcohols

Chemistry
1 answer:
liq [111]3 years ago
3 0
You forgot to add pictures ..
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Two atoms of calcium and one molecule of oxygen gas react and yield two molecules of calcium oxide.
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List four elements used in dfds, draw the symbols, and explain how they are used.
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Which solution has the greatest osmolarity?
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Watch the animation depicting Rutherford’s experiment and choose which of the following conclusions are correct.a. The atom cont
Lilit [14]

Answer:

a, b, c, d

Explanation:

Rutherford’ atomic model is based on the gold foil experiment. In this experiment, beam of alpha rays was bombarded on thin gold foil. He observed that:

Most of the alpha particles passed through thin foil without any deflection.

Few alpha particles deflected by an angle of 90o.

Based on observation, Rutherford concluded that majority of the space inside the atom is empty.

He explained defection of few alpha particles by assuming that most of the mass is concentrated at the nucleus and positively charged.  

Therefore, among given, the correct statements are:

The atom contains a positively charged nucleus.

Positive charge is condensed in one location within the atom.

The majority of the space inside the atom is empty space

The mass of an atom is concentrated at the nucleus

Therefore, the correct options are:

a, b, c, d

4 0
3 years ago
How many molecules of co2 in 97.3 grams of co2
s2008m [1.1K]

Answer:

1.33 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Reading a Periodic Table
  • Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

97.3 g CO₂

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

97.3 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.33138 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂

8 0
3 years ago
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