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yan [13]
3 years ago
10

What’s negative and positive on y axis and x axis

Mathematics
1 answer:
aksik [14]3 years ago
8 0
Hello.


Mark off a number line with zero in the center, positive numbers going upwards, and negative numbers going downwards. The point where the x and y axes intersect is called the origin. The origin is located at zero on the x axis and zero on the y axis.
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Step-by-steps:

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A coin is tossed 8 times. What is the probability of getting all heads? Express your answer as a simplified fraction or a decima
kumpel [21]

Answer:

The probability of getting all heads is \frac{1}{256}.

Step-by-step explanation:

For each time the coin is tossed, there are only two possible outcomes. Either it is heads, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

A coin is tossed 8 times. This means that n = 8

In each coin toss, heads or tails are equally as likely. So p = \frac{1}{2}

What is the probability of getting all heads?

This is P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

[tex]P(X = 8) = C_{8,8}*(\frac{1}{2})^{8}*(1 - \frac{1}{2})^{0} = \frac{1}{256}

The probability of getting all heads is \frac{1}{256}.

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3 years ago
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Answer:

Yes, Hamdan is correct.

Step-by-step explanation:

Let the two fractions are q/r and s/r.

Here, the denominator is same for both the fractions.

So, as we add them, add the numerators and the denominators remains same.

\frac{q}{r}+\frac{s}{r}\\\\=\frac{q + s}{r}

For example

\frac{3}{5}+\frac{4}{5}\\\\=\frac{3 + 4}{5}\\\\=\frac{7}{5}

So, Hamdan is correct.

6 0
2 years ago
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