(u^2 - 4) / (u-6)(u-2)
Resriction u ≠ 6 and u ≠ 2 (because the denominator cannot be equal lto zero)
Simplification
u^2 - 4 is a difference of two squares, then you can factor it as the product of (u+2)(u-2). So, you can write the expression as:
(u+2)(u-2) / (u-2)(u-6)
Simplify u -2 (because it appears in the numerator and the denominator)
(u + 2) / (u -6), with u ≠2 and u≠6
A and D i think.(sry this needed to be 20 characters long)
Equation of a line passing through point (x1, y1) with slope m is given by y - y1 = m(x - x1)
y - 2 = -1/2(x - 6)
2(y - 2) = -(x - 6)
2y - 4 = -x + 6
x + 2y = 6 + 4
x + 2y = 10
This is a question of resolving the forces in question into horizontal and vertical and then finding the action of the resultant force.
The first force acts at an angle less than 90° and thus its resolved forces are positive. The second force acts at angle larger than 90° and is incident and thus its horizontal value is positive while its vertical value is negative.
Therefore;
For force of 300 N at 30°;
Horizontal value = 300*Cos 30 = 259.81 N
Vertical value = 300*Sin 30 = 150 N
For 150 N at 135°;
Horizontal value = 150*Cos (180-135) = 106.07 N
Vertical value = -150*Sin (180-135) = -106.07 N
Then,
Resultant horizontal value = 259.81+106.07 = 365.88 N
Resultant vertical value = 150-106.07 = 43.93 N
Therefore,
Resultant force, v = Sqrt (365.88^2+43.93^2) = 368.51 N
Angle of action measured from horizontal = tan ^-1(43.93/365.88) 6.85°
Then,
v = 368.51 N at 6.85° from horizontal
Answer:
a) x=25+0.06y
b)x=25+0.06*30=£26.80
c)x=25+0.06*200=£37
d)x=25+0.06y ; 43=25+0.06y ; 43-25=0.06y ; 18=0.06y ; y=18÷0.06 ; y=300 messages
Step-by-step explanation:
aaaaaa hope theyre correct