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sattari [20]
3 years ago
10

10 PTS!!!! PLEASE HELP ALGEBRA 1 MATH

Mathematics
1 answer:
Alex787 [66]3 years ago
3 0
Parallel lines will always have the same SLOPE. In the case of this equation, the slope is 1 since x is the same as 1x and the coefficient of x is the slope. Because there is no y, the graph of the equation will NEVER intercept the y-axis. Therefore, whatever answer option does not have y is correct.

Answer: C. x=2

Here's the graph to help you visualize: 


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Which expression is in simplified form for the given expression and states the correct variable restriction?
storchak [24]
(u^2 - 4) / (u-6)(u-2)

Resriction u ≠ 6 and u ≠ 2 (because the denominator cannot be equal lto zero)

Simplification

 u^2 - 4 is a difference of two squares, then you can factor it as the product of (u+2)(u-2). So, you can write the expression as:

(u+2)(u-2) / (u-2)(u-6)

Simplify u -2 (because it appears in the numerator and the denominator)

(u + 2) / (u -6), with u ≠2 and u≠6
5 0
4 years ago
Which of the following expressions have a
Yuki888 [10]
A and D i think.(sry this needed to be 20 characters long)
7 0
3 years ago
Indicate in standard form the equation of the line passing through the given point and having the given slope.
Svetradugi [14.3K]
Equation of a line passing through point (x1, y1) with slope m is given by y - y1 = m(x - x1)
y - 2 = -1/2(x - 6)
2(y - 2) = -(x - 6)
2y - 4 = -x + 6
x + 2y = 6 + 4
x + 2y = 10
8 0
3 years ago
Two forces act on an object. The first Force has a magnitude of 300 Newtons and acts at an angle of 30 degrees as measured from
alina1380 [7]
This is a question of resolving the forces in question into horizontal and vertical and then finding the action of the resultant force.
The first force acts at an angle less than 90° and thus its resolved forces are positive. The second force acts at angle larger than 90° and is incident and thus its horizontal value is positive while its vertical value is negative.

Therefore;
For force of 300 N at 30°;
Horizontal value = 300*Cos 30 = 259.81 N
Vertical value = 300*Sin 30 = 150 N

For 150 N at 135°;
Horizontal value = 150*Cos (180-135) = 106.07 N
Vertical value = -150*Sin (180-135) = -106.07 N

Then,
Resultant horizontal value = 259.81+106.07 = 365.88 N
Resultant vertical value = 150-106.07 = 43.93 N

Therefore,
Resultant force, v = Sqrt (365.88^2+43.93^2) = 368.51 N
Angle of action measured from horizontal = tan ^-1(43.93/365.88) 6.85°

Then,
v = 368.51 N at 6.85° from horizontal
5 0
4 years ago
Help me please I beg
likoan [24]

Answer:

a) x=25+0.06y

b)x=25+0.06*30=£26.80

c)x=25+0.06*200=£37

d)x=25+0.06y ; 43=25+0.06y ; 43-25=0.06y ; 18=0.06y ; y=18÷0.06 ; y=300 messages

Step-by-step explanation:

aaaaaa hope theyre correct

7 0
3 years ago
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