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lora16 [44]
3 years ago
15

Find the equation of a line that is perpendicular to line g that contains (P, Q). coordinate plane with line g that passes throu

gh the points negative 2 comma 6 and negative 3 comma 2
Mathematics
1 answer:
maw [93]3 years ago
7 0

Answer:

y - Q =  -  \frac{1}{4}(x - P)

Step-by-step explanation:

Line g passes through (-2,6) and (-3,2).

The slope of line g is given by:

\frac{ y_2-y_1}{x_2-x_1}

Let's substitute the values to get:

\frac{2 - 6}{ - 3 -  - 2}= \frac{ - 4}{ - 1}  = 4

The equation that is perpendicular to line g will have a slope that is the negative reciprocal of 4.

i.e -1/4

If this line passes through (P,Q), then the equation is:

y - Q =  - \frac{1}{4} (x - P)

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