Question

Find the equation of a line that is perpendicular to line g that contains (P, Q). coordinate plane with line g that passes through the points negative 2 comma 6 and negative 3 comma 2

Answer 1

Answer:

$y - Q = - \frac{1}{4}(x - P)$

Step-by-step explanation:

Line g passes through (-2,6) and (-3,2).

The slope of line g is given by:

$\frac{ y_2-y_1}{x_2-x_1}$

Let's substitute the values to get:

$\frac{2 - 6}{ - 3 - - 2}= \frac{ - 4}{ - 1} = 4$

The equation that is perpendicular to line g will have a slope that is the negative reciprocal of 4.

i.e -1/4

If this line passes through (P,Q), then the equation is:

$y - Q = - \frac{1}{4} (x - P)$