Answer:
2.95 * 10^23 atoms
Explanation:
The number of atoms in a mole is always equal to <u>Avogadro's constant</u>, which is <u>6.02214076×10²³ mol⁻¹</u>.
To find the number of atoms in 0.490 moles of barium, multiply it with <u>Avogadro's constant</u>:
0.490 mol * 6.02214076×10²³ mol⁻¹ ≈ 2.9508 * 10^23
Convert to SigFigs (if necessary):
2.95 * 10^23
Answer:
https://www.webassign.net/question_assets/wertzcams3/appendix.pdf
Answer:
Define a problem, form a hypothesis, gather experimental data, form a conclusion
Given :
Volume of NaCl solution 2.5 L .
Molarity of NaCl solution is 0.070 M .
To Find :
How many moles are present in the solution.
Solution :
Let, n be the number of moles.
We know, molarity is given by :

So,

Therefore, number of moles of NaCl is 0.175 moles.