Answer: 1.
moles
2. 90 mg
Explanation:

According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus
moles of ozone is removed by =
moles of sodium iodide.
Thus
moles of sodium iodide are needed to remove
moles of 
2. 
According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus 0.0003 moles of ozone is removed by =
moles of sodium iodide.
Mass of sodium iodide=
(1g=1000mg)
Thus 90 mg of sodium iodide are needed to remove 13.31 mg of
.
Answer:
okay let me know when i can help, ill be happy too help
Because they don't care and think the ozone layer is fine.
The correct answers would be A, and D
Answer:
An addition reaction
Step-by-step explanation:
In an addition reaction, two or more molecules come together to form a single product, for example,
C₂H₂ + 2Cl₂ ⟶ C₂H₂Cl₄
This reaction consists of two successive additions. The product of the first reaction becomes a reactant and adds a second molecule of Cl₂ to form C₂H₂Cl₄
C₂H₂ + Cl₂ ⟶ <em>C₂H₂Cl₂
</em>
<em><u>C₂H₂Cl₂</u></em><u> + Cl₂ ⟶ C₂H₂Cl₄
</u>
C₂H₂ + 2Cl₂ ⟶ C₂H₂Cl₄