All categories

3 years ago

ll of the following cause mechanical weathering EXCEPT ____. a. ice c. burrowing animals b. tree roots d. carbonic acid

1 answer:

4 0

All of the following cause mechanical weathering EXCEPT d. carbonic acid, which causes chemical weathering. Mechanical weathering is defined as a physical process where rocks are broken down into smaller pieces through movement, abrasion, pressure, and temperature changes. Chemical weathering, on the other hand, makes use of chemical reactions to break down rocks.

You might be interested in

If a substance has a temperature of 273 kelvins, what is its temperature in degrees celsius?

kipiarov [429]

It is at 0 degrees Celsius

5 0

3 years ago

Is sugar an element or a molecure or a molecure and a compound?

shepuryov [24]

Answer:

Compound

Explanation:

Table sugar, or sucrose, is a compound because it's formed when two or more elements are joined together. Its chemical formula is C12H22O11, and it contains carbon, hydrogen and oxygen.

6 0

3 years ago

Question 1 (3 points)

den301095 [7]

Answer:

Explanation:

ΔTemp => 35⁰C(108K) increases to 57.9⁰C(330.9L) => increases volume (Charles Law)

Use the Kelvin Temperature values in a ratio that will increase the original volume.

ΔVol = 6.33L(330.9/108.0) => gives a larger volume. Using 108.0/330.9 would give a smaller volume and would be contrary to what the problem is asking.

ΔPress => 342 mmHg increases to 821 mmHg => decreases volume (Boyles Law)

Use the pressure values in a ratio that will decrease the original volume.

ΔPress = 6.33L(342/821) => gives a smaller volume. Using 821/342 would give a larger volume and would be contrary to what the problem is asking.

Now, putting both ΔTemp together with ΔPress => net change in volume. (Combined Gas Law)

ΔVol = 6.33L(330.9/108.0)(342/821) = 8.08L (final volume of gas).

___________________

This problem can also be worked using the combined gas law equation:

P₁V₁/T₁ = P₂V₂/T₂ => V₂ = P₁V₁T₂/T₁P₂

V₂ = [(342mm)(6.33L)(330.9K)]/[(108K)(821mm)] = 8.08L (final volume of gas)

7 0

3 years ago

Calculate the mass, in grams, of Al(OH)3 required for this reaction:

AVprozaik [17]

Answer:

Mass = 28.08

Explanation:

Given data:

Mass of Al₂O₃ = 21.8 g

Mass of water = 9.7 g

Mass of Al(OH)₃ = ?

Solution:

Chemical equation:

2Al(OH)₃ → Al₂O₃ + 3H₂O

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 9.7 g/ 18 g/mol

Number of moles = 0.54 mol

Number of moles of Al₂O₃:

Number of moles = mass/molar mass

Number of moles = 21.8 g/ 101.96 g/mol

Number of moles = 0.21 mol

Now we will compare the moles of Al(OH)₃ with Al₂O₃ and H₂O.

Al₂O₃ : Al(OH)₃

1 : 2

0.21 : 2×0.21 = 0.42 mol

H₂O : Al(OH)₃

3 ; 2

0.54 : 2/3×0.54 = 0.36 mol

Mass of Al(OH)₃:

Mass = number of moles × molar mass

Mass = 0.36 mol × 78 g/mol

Mass = 28.08 g

3 0

3 years ago

A food is initially at a moisture content of 90% dry basis. Calculate the moisture content in wet basis

Anvisha [2.4K]

Answer:

Moisture content in wet basis = 47.4 %

Explanation:

Moisture content expresses the amount of water present in a moist sample. Dry basis and wet basis are widely used to express moisture content.

The next equation express the moisture content in wet basis:

$MC_{wb}=\frac{MC_{db}}{1+MC_{db}}$

where, $MC_{wb}$ : moisture content in wet basis and

$MC_{db}$ : moisture content in dry basis

We now calculate the moisture content in wet basis:

$MC_{wb}=\frac{MC_{db}}{1+MC_{db}}$

$MC_{wb}=\frac{0.90}{1+0.90}$

$MC_{wb}$ = 0.474 = 47.4 % wet basis

Have a nice day!

8 0

4 years ago