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Natasha_Volkova [10]
3 years ago
9

Magnesium hydroxide (Mg(OH)2): g/mol Iron(III) oxide (Fe2O3): g/mol

Chemistry
2 answers:
steposvetlana [31]3 years ago
6 0

Molecular mass of Mg(OH)2

= Atomic mass of Mg + 2(Atomic mass of O) + 2(Atomic mass of H)

= 24 g/mol + 2(16 g/mol) + 2(1 g/mol )

= 58 g/mol

Molecular mass of Fe2O3

= 2(Atomic mass of Fe) + 3(Atomic mass of O)

= 2(56 g/mol) + 3(16 g/mol)

= 160 g/mol

alekssr [168]3 years ago
5 0
Magnesium Hydroxide= 58.33
Iron (III) Oxide= 159.70
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Number of moles of H₂O =  \frac{1.09}{18} = 0.06mole

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                           0.03                                    0.06

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Ratio                  0.03/0.03                         0.03/0.06

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