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Andru [333]
3 years ago
5

How many moles are 2.54 x 10^29 molecues of H2O

Chemistry
1 answer:
shtirl [24]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 421,786.7818 \ mol \ H_2O}}

Explanation:

We are asked to convert from molecules of water to moles.

<h3>1. Avogadro's Number </h3>

1 mole of any substance contains the same number of particles (atoms, molecules, formula units, etc). This is Avogadro's Number: 6.022*10²³. In this problem, the particles are molecules of water.

<h3>2. Convert Molecules to Moles</h3>

Use Avogadro's Number to make a ratio.

\frac {6.022 *10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}

Multiply by the number of molecules given: 2.54 *10²⁹

2.54 *10^{29}  \ molecules \ H_2O \times \frac {6.022 *10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}

Flip the ratio so the units of molecules of water cancel.

2.54 *10^{29}  \ molecules \ H_2O \times \frac {1 \ mol \ H_2O}{6.022 *10^{23} \ molecules \ H_2O}

2.54 *10^{29}   \times \frac {1 \ mol \ H_2O}{6.022 *10^{23} }

Condense the problem into 1 fraction.

\frac {2.54 *10^{29} }{6.022 *10^{23} }\ mol \ H_2O

421786.7818 \ mol \ H_2O

2.54 *10²⁹ molecules of water are 421, 786.7818 moles of water.

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Answer:

       \large\boxed{\large\boxed{0.291M}}

Explanation:

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For a <em>second order reaction </em>the rate law equations are:

              \dfrac{d[B]}{dt}=-k[B]^2

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