It is given that there are 41 males and 48 females in the small school.
So, the number of ways a male student can be chosen from 41 males is 
Likewise, the number of ways a female student can be chosen from 48 females is 
.
Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:
A, 25.376. This rounded to the nearest hundredth would be 25.38 not 25.37.
Answer:
k=10
Step-by-step explanation:
g(x)=2x^2+ kx+18
when x=-2
g(-2)=2 (-2)^2 -2k +18
Since when x is -2, y =6
6=2 (-2)^2 -2k +18
6=18+8-2k
2k=26-6
2k=20
k=10
The team has lost only 6 games (according to the comments). Let's say "x" is the amount of losses and "y" is the amount of wins.
For every loss, they have 3 wins, so in the end, this would be the equation:
or
Although the first one would be the easier and most understandable to read.
So:
y = 3(6)
would equal
18
Is that all the question says can you give it into more details
So I can help you out
