Ask question

Ask question

All categories

3 years ago

13

What category does -1/3 belong in? (Select all that apply) Rational Number Rational Number Integer Number Integer Number Natural

Number Natural Number Whole Number

1 answer:

Aleksandr [31]3 years ago

4 0

Answer:

1/3 is a rational number

Step-by-step explanation:

You might be interested in

Part B if the height of each prism is 10 Cm what is the surface area prism

Evgen [1.6K]

Answer:

Prism A:

$Area = 288cm^2$

Prism B:

$Area =250cm^2$

Step-by-step explanation:

Given

See attachment for prisms

$Height(h) = 10cm$

Required

Determine the surface area of both prisms

Prism A is triangular and as such, the surface area is:

$Area = 2 * A_b + (a + b + c) * h$

Where

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

and

$s = \frac{a + b + c}{2}$

Such that a, b and c are the lengths of the triangular sides of the prism.

From the attachment;

$a = 8; b =6; c =10$

So, we have:

$s = \frac{a + b + c}{2}$

$s = \frac{8 + 6 + 10}{2}$

$s = \frac{24}{2}$

$s = 12$

Also:

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

$A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}$

$A_b = \sqrt{576}$

$A_b = 24$

So:

$Area = 2 * A_b + (a + b + c) * h$

$Area = 2 * 24 + (8 + 6 + 10) * 10$

$Area = 288cm^2$

Prism B is a rectangular prism. So, the area is calculated as:

$Area = 2 * (ab + bh + ah)$

From the attachment

$a = b = 5$

$h =10$

So:

$Area =2 * (5 * 5 + 5 * 10 + 5 * 10)$

$Area =250cm^2$

7 0

2 years ago

What inequality is shown in the graph? Please help and thanks in advance!

konstantin123 [22]

Greater than because the line is dashed and the shaded region is in the positive or less negative numbers area. Greater than or equal would be the same but with a solid line.

5 0

3 years ago

Find the area of the triangle.

BabaBlast [244]

Answer:

17.7 cm^2

Step-by-step explanation:

Use trig to find the height of the triangle. Then the area is bh/2.

Extend side BC to the right until it is vertically below point A. Draw a segment from point A vertically down until it intersects the extension of side BC. Call the point of intersection D. <D is a right angle.

Use triangle ABD to find the height, AD, of triangle ABC.

For <B of 37 deg, AD is the opposite leg. AB is the hypotenuse. The trig ratio that relates the opposite lefg to the hypotenuse is the sine.

sin B = opp/hyp

sin 37 deg = AD/13.1

AD = 13.1 * sin 37 deg

AD = 7.9

AD is the height of triangle ABC. BC is the base. We can find the area of triangle ABC.

area = bh/2

area = (4.5 cm)(7.9 cm)/2

area = 17.7 cm^2

5 0

3 years ago

Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i

steposvetlana [31]

Answer:

The distance between the two given complex numbers = 9

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i):</em></u>-

Given Z₁ = 9 - 9 i and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A = Z₁ = x₁ +i y₁ = 9 - 9 i and

B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

(x₂, y₂) = (10, -9)

<u>Step(ii)</u>:-

<em>The distance between the two points are </em>

A B = $\sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2} }$

A B = $\sqrt{(10 - 1)^{2}+(-9 - (-9))^{2} }$

AB = $\sqrt{(9)^{2} +(-9+9)^{2} }$

<em> AB = √81 = 9</em>

<u><em>Conclusion:-</em></u>

The distance between the two given complex numbers = 9

<u><em></em></u>

3 0

3 years ago

A man traveled a certain number of miles by automobile and then nine times as far by airplane. His total trip was 600 miles in l

Alex17521 [72]

The miles he traveled by plane is nine times greater than the miles traveled by automobile. If the total is 600 miles, then the total distance traveled by automobile would be 60 miles, making the total traveled by airplane 540 miles.

4 0

3 years ago