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kifflom [539]
3 years ago
12

In a fifth grade class 4/5 of the girls have brown hair 3/4 of them have Long hair what fraction have Long brown hair

Mathematics
2 answers:
Olenka [21]3 years ago
7 0

Answer:

\frac{3}{5}

Step-by-step explanation:

We have that,

Fraction of girls having brown hair = \frac{4}{5}

Fraction of girls having long hair = \frac{4}{5}

Thus, the fraction of girls having long brown hair = Fraction having brown hair × Fraction having long hair

i.e. Fraction of girls having long brown hair = \frac{4}{5}\times \frac{4}{5}

i.e. Fraction of girls having long brown hair = \frac{3}{5}

Hence, the fraction of girls having long brown hair is  \frac{3}{5}.

maxonik [38]3 years ago
3 0
ANSWER: 12/20 or 3/5

4/5 of girls have brown hair
3/4 have long hair

\frac{4}{5} * \frac{3}{4} = \frac{12}{20}
\frac{12}{20} / \frac{4}{4} = \frac{3}{5}
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Olivia is on a road trip with her family. During a three-hour stretch, they traveled 183 miles. How fast were they driving in mi
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Can anyone please help me on this question I’m kinda stuck.
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They are the same

Step-by-step explanation:

The degree is basically all of the exponents added up. So:

A) 2+4 = 6

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How tall is a building that casts a 61-fit shadow when the angle of elevation of the sun is 60 degrees?
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Step-by-step explanation:

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A farmer wants to know which of two fertilizers will yield the most produce. He sets up twenty random plots of equal size on one
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<h2>Answer:</h2>

A)

Mean for:

Sample Z --  447.5

Sample Y-- 409.3

B)

Sample Y has larger deviation from the mean.

<h2>Step-by-step explanation:</h2>

Z Plots      Y Plots  

 456          395

 454          390

 449          391

 453          402

 431           395

 456          405

 445          432

 430          438

 463          420

 438          425

A)

For sample Z--

The mean is calculated by:

Ratio of sum of all the data points of Z-sample to the total number of points i.e. 10.

Mean=\dfrac{456+454+449+453+431+456+445+430+463+438}{10}\\\\Mean=\dfrac{4475}{10}\\\\Mean=447.5

Similarly for sample Y--

The mean is calculated as follows:

Mean=\dfrac{395+390+391+402+395+405+432+438+420+425}{10}\\\\\\Mean=\dfrac{4093}{10}\\\\Mean=409.3

B)

As we could see that the data Y has a greater spread from the mean as compared to the sample Z.

As all the points in the sample Z are close to the mean and have less spread.

The standard deviation is most commonly used to measure the spread of the data.

Standard deviation of sample Z is: 10.651

Standard deviation of sample Y is: 16.9944

Hence Sample Y have larger deviation from the mean.

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3 years ago
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