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Pavlova-9 [17]
3 years ago
8

The steps Quentin took to evaluate the expression 3m - 3+3 when m = 8

Mathematics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

Subtracted 3 from (24+3)

Step-by-step explanation:

3m - 3 + 3

24 - 3 + 3

Since the adding and subtracting go left to right, you can do them in that order.

21+3 = 24.

Now which one gives us 24?

(24+3) - 3

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raw and label a model to find the value of 3··81 4·· 8. Then write and solve an equation that matches the model.
bagirrra123 [75]

For is mathematically given as

<h3>What is the solution of an equation that matches the model.?</h3>

Considering line segments from (0,0,0)origin to (3,0,0) , (3,5,1) and (0,5,1) under the infulence of force

Generally,  the equation for force is mathematically given as

F = z2i + 5xyj + 2y2k

Therefore, Considering u*v

u * v = (u_1j+u_2j+u_3k) * (v_1i+v_2j+v_3k)

u* v = u_1v_1(i * i) + u_1v_2(i * j)+u_1v_3(i * k) + u_2v_1(j * i) + u_2v_2(j * j)+u_2_3(j* k) + u_3v_1(k * i) + u_3v_2(k * j)+u_3v_3(k * k)

Where

i * i = j *j=k * k=0

Hence

u* v = u_1v_2k-u_1v_3j-u_2v_1k+u_2v_3i +u_3v_1j - u_3v_2i

u = (u_1,u_2,u_3) = (0,5,1)\\\\v = (v_1,v_2,v_3) = (-3,0,0)

The normal equation formed

-3y + 15z = 0

z= (1/5)y

Considering the level surface and differential surface area

h(x,y,z) = -y + 5z =0

dS = |grad(h)| dA

In terms of the x and y coordinates of (3,0,0) and (3,5,1) and (0,5,1), we can state that the ranges are 0 to 3 and 5 respectively.

In conclusion,

Read more about

#SPJ1

6 0
2 years ago
Solve hav etojfoslfnownfosnfosdnfosdldfn<br> 3y – 36 = 9y
Gnom [1K]
Y=-6 hope this helps
5 0
3 years ago
Having a hard time understanding these transformations. Thank you!​
Oksanka [162]

Answer:

1). For < 4 Coordinates will be A"( -2,2),B"(1,-1),C"(-3,-2).

   For 1 > Coordinates will be A"(3,2), B"(6,-1), C(2,-2).

2). A"(-2,2), B"(-1,-2), C"(-5,-1).

Step-by-step explanation:

1) In this part of the question we have to find the new coordinates of the triangle when there is a shift of 4 in left means the new coordinates will be A"( 2-4,2),B"(5-4,-1),C"(1-4,-2) Or  A"( -2,2),B"(1,-1),C"(-3,-2).

And when shifted by 1 in right direction A,B,C will be A",B",C" that are A"( 2+1,2),B"(5+1,-1),C"(1+1,-2) Or A"(3,2), B"(6,-1), C(2,-2).

2) Now we have to get the reflection of points A(2,2), B(5,-1), C(1,-2) across Y axis.

When A reflects about Y axis it will reflect in Second quadrant. So new coordinates will be A"(-2,2).

Similarly B and C will reflect in third quadrant. So new coordinates will be B"(-1,-2) & C"(-5,-1).

8 0
3 years ago
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