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ivann1987 [24]
4 years ago
11

A basic solution contains an excess of H^+ ions. O True O False

Chemistry
1 answer:
Lina20 [59]4 years ago
4 0

Answer:

true

Explanation:

Yes basic solutions also have H+ ions.

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Please help me with this chemistry question. Image attached.
Leya [2.2K]

Answer:

Moles of zinc chloride produced are 0.09942 moles.

Explanation:

Zn+2HCl\rightarrow ZnCl_2+H_2

Mass of zinc used = 6.5 g

Moles of zinc =\frac{6.5 g}{65.38 g/mol}=0.09942 mol

According to reaction, 1 mol of zinc gives 1 mole of zinc chloride,then 0.09942 moles of zinc will give :

\frac{1}{1}\times 0.09942 =0.09942 mol of zinc chloride

Moles of zinc chloride produced are 0.09942 moles.

3 0
3 years ago
What type of bond is formed between metal ions and nonmetal ions?
Lostsunrise [7]
Ionic is metal and nonmetal
5 0
3 years ago
Read 2 more answers
The atomic number of sulfur is 16, which indicates that a sulfur atom contains
zvonat [6]
<span>The atomic number of an element indicates only how many protons are in that specific element. The atomic number of sulfur is 16, so it means that in one sulfur atom, there are 16 protons. The number of protons is also equal to the number of electrons in any given atom, so this number also indicates that there are 16 electrons in a sulfur atom.</span>
8 0
4 years ago
1.
snow_tiger [21]
There are 1,000m is 1k. So just move the decimal one position right. 127.56m

There are 10,000cm in 1k. Move the decimal two positions right. 1275.6cm
5 0
4 years ago
Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r
MakcuM [25]

Answer:

CH2O

Explanation:

Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.

C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

6 0
4 years ago
Read 2 more answers
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