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Rasek [7]
3 years ago
15

List four examples of diffusion seen in daily life.

Chemistry
1 answer:
babunello [35]3 years ago
6 0

Answer:

Spraying perfume in one corner of the room and the smell travels to the other side of the room

Explanation:

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Ammonia is produced industrially via this exothermic reaction.
Cloud [144]

Answer:

high pressure of 200-300 atm.

low temp. of between 400-500 degrees celsius:this is for continuous development of ammonia since it decomposes at high temp fathermore the reaction is exothermic

a catalyst to speed up the rate of reaction:i guess it is finely divided iron impregnated in aluminium oxide

platinum can be used as a catalyst but it is easily poisoned

hope it helps

Explanation:

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3 years ago
How is electronegativity related to covalent bonding?
Vinvika [58]
Covalent bonds form when atoms share electrons. This sharing allows each atom to achieve its octet of electrons and greater stability. Methane, CH 4<span>, the simplest organic compound, contains covalent bonds. Carbon has four valence electrons, while hydrogen has one valence electron. By sharing these outer‐shell electrons, carbon and hydrogen complete their valence shells and become more stable. The duet of electrons on the hydrogen is isoelectronic with helium and forms a complete shell.</span>
4 0
3 years ago
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J.
timofeeve [1]

Complete question:

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.

Answer:

The magnitude of q for the process 568 J.

Explanation:

Given;

change in internal energy of the gas, ΔU = 475 J

work done by the gas, w = 93 J

heat added to the system, = q

During gas expansion process, heat is added to the gas.

Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.

ΔU = q - w

q = ΔU +  w

q = 475 J  +  93 J

q = 568 J

Therefore, the magnitude of q for the process 568 J.

6 0
3 years ago
Compared with halogens, the alkali metals in the same period has
Rufina [12.5K]
Alkali metals have the lowest electronegativities, while halogens have the highest.
3 0
3 years ago
When the equation Ca(OH)2 + HBr → (products) is completed and balanced, one term in the equation will be
NISA [10]
<span>Answer for the given question is CaBr2. Although, the given equation requires balancing of by adding one more HBr and one more H2o in resultant. The given equation will product at least one CaBr2. Hence the answer for the given equation is Calcium bromide i.e. CaBr2.</span>
4 0
3 years ago
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