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Korvikt [17]
3 years ago
12

What is the mass of 6.00 cm^3 of mercury, density = 13.5939 g/cm^3?

Chemistry
1 answer:
Molodets [167]3 years ago
5 0

Answer: 81.5634kg

Explanation:

Density=mass/volume

13.5939=m/6

make m subject of formula

m= 13.5939×6

m=81.5634kg

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Alex_Xolod [135]
Simple molecular biology
8 0
3 years ago
Describe the three main types of plate boundary interactions:
bulgar [2K]

Answer:

In the explanation

Explanation:

Divergent: When two plates are diverging from each other, meaning that the two plates are moving away from each other. Events that may occur include ridges or rifts.

Convergent: When two plates are moving towards each other.

If a continental plate and an oceanic plate are converging, the oceanic plate would slide underneath the continental plate since it is thinner. This would result in subduction, which means that part of the oceanic plate would hang underneath the continental plate, where magma can melt the hanging part.

If two continental plates are converging, the crash would result in mountains or volcanic activity. Magma could rise and rush from the crack. There would be a bump in these tectonic plates.

Transform: When two plates are sliding past each other. Earthquakes can occur when the plates are sliding. When an oceanic plate is involved, the movement of the plates could cause a tsunami as well. The water above the transform fault could rise, and grow bigger and bigger. The 2011 Japan Tsunami is a good example of this.

Hope this helps!

5 0
3 years ago
What is Δn for the following equation in relating Kc to Kp?2 SO2(g) + O2(g) ↔ 2 SO3(g)23-2-11
san4es73 [151]

Answer:

-1

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2SO_2_{(g)}+O_2_{(g)}\rightleftharpoons2SO_3_{(g)}

<u>Δn = (2)-(2+1) = -1  </u>

Thus, Kp is:

K_p=  K_c\times (RT)^{-1}

4 0
3 years ago
I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
3 years ago
At constant force, acceleration varies (directly, inversely) with mass. When subjected to the same amount of net external force,
lora16 [44]

Answer:

I don't know the ans please search on the Google you will get

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7 0
3 years ago
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