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Korvikt [17]
3 years ago
12

What is the mass of 6.00 cm^3 of mercury, density = 13.5939 g/cm^3?

Chemistry
1 answer:
Molodets [167]3 years ago
5 0

Answer: 81.5634kg

Explanation:

Density=mass/volume

13.5939=m/6

make m subject of formula

m= 13.5939×6

m=81.5634kg

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29.47 mL of a solution of the acid HBr is titrated, and 72.90 mL of 0.2500-M NaOH is required to reach the equivalence point. Ca
Klio2033 [76]

The original concentration of the acid solution is 6.175 \times 10^-4 mol / L.

<u>Explanation:</u>

Concentration is the ratio of solute in a solution to either solvent or total solution. It is expressed in terms of mass per unit volume

                        HBr + NaOH -----> NaBr + H2O

There is a 1:1 equivalence with acid and base.

Moles of NaOH = 72.90 \times 10^-3 \times 0.25

                          = 0.0182 mol.

[ HBr ] = moles of base / volume of a solution

          = 0.0182 / 29.47

          = 6.175 \times 10^-4 mol / L.

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An atom was observed with +3 charge, n = 38, and e = 28. What is the mass number of the atom?
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Which of the following are examples of conservable quantities? a. potential energy and length c. mechanical energy and mass b. m
Blababa [14]

Answer:

b

Explanation:

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3 years ago
What does the interquartile range represent?
Marizza181 [45]

Answer: C) middle 50 percent of the data

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25% of the data is below Q1 and 75% of the data is below Q3. The gap between the two endpoints consists of 75-25 = 50 percent of the data, or half of the data.

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Calculate how much heat is absorbed by a sample that weighs 12 kilograms, has a specific heat of 0.231 kg/CJ, and is heated from
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Answer:

97 J

Explanation:

Step 1: Given data

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Step 2: Calculate the temperature change

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We will use the following expression.

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3 years ago
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