Answer:
The percent yield of the reaction is 48.05%
Explanation:
We have the following balanced reaction:
Cu + 2HNO3 = Cu(NO3)2 + H2
The moles of copper is equal to:
moles Cu = 0.5674 g/63.54 g/mol = 0.0089 moles
The moles of HNO3 is equal to:
moles HNO3 = 10 mL * (1 L/1000 mL) * 16 M = 0.16 moles
The mass of Cu produced is equal to:
mass of Cu(NO3)2 = moles of Cu(NO3)2 * molar mass Cu(NO3)2
mass of Cu(NO3)2 = 0.0089 mol * 187.56 g/mol = 1.67 g
The percent yield is equal to:
percent yield = (0.8024/1.67)*100 = 48.05%
