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4 years ago

The Release Train Engineer is a servant leader who displays which two actions or behaviors?

Engineering

1 answer:

IrinaK [193]4 years ago

6 0

Explanation:

The Release Train Engineer (RTE) has the main work of supporting as well as coaching the Agile Release Train (ART). They are capable of steering ART successfully and to navigate the complexity in delivering the software in large and inter-functional environments.

They serve the scrum master and coach teams to improve on the results.

The two actions or behaviors of the RTE are :

1. They try to create an environment of the mutual influence.

2. Listens and also supports the teams in problem identification as well as decision-making.

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How to pass sharp edged tools to another student in welding

lisov135 [29]

Answer: When walking with a sharp tool, the tool should be carried with the blade down and away from the body. When climbing with a sharp tool, tool belts, or buckets with hand lines should be used so workers can have both hands to grip the ladder.

Explanation:

3 0

3 years ago

Why the velocity potential Φ(x,y,z,t) exists only for irrotational flow

Black_prince [1.1K]

Answer:

$\omega_y,\omega_x,\omega_Z$ all are zero.

Explanation:

We know that if flow is possible then it will satisfy the below equation

$\dfrac{\partial u}{\partial x}+\dfrac{\partial v}{\partial y}+\dfrac{\partial w}{\partial z}=0$

Where u is the velocity of flow in the x-direction ,v is the velocity of flow in the y-direction and w is the velocity of flow in z-direction.

And velocity potential function $\phi$ given as follows

$u=-\frac{\partial \phi }{\partial x},v=-\frac{\partial \phi }{\partial y},w=-\frac{\partial \phi }{\partial z}$

Rotationality of fluid is given by $\omega$

$\frac{\partial v}{\partial x}-\frac{\partial u}{\partial y}=\omega_Z$

$\frac{\partial v}{\partial z}-\frac{\partial w}{\partial y}=\omega_x$

$\frac{\partial w}{\partial x}-\frac{\partial u}{\partial z}=\omega_y$

So now putting value in the above equations ,we will find

$\omega =\frac{\partial \phi }{\partial x},u=\frac{\partial \phi }{\partial x},$

$\omega_y=\dfrac{\partial^2 \phi }{\partial z\partial x}-\dfrac{\partial^2 \phi }{\partial z\partial x}$

So $\omega_y$ =0

Like this all $\omega_y,\omega_x,\omega_Z$ all are zero.

That is why velocity potential flow is irroational flow.

5 0

4 years ago

1 UNREAD MESSAGE

myrzilka [38]

Answer:

triangular trade

Explanation:

triangular trade

7 0

2 years ago

2.) A fluid moves in a steady manner between two sections in a flow

Talja [164]

Answer:

$250\ \text{lbm/min}$

$625\ \text{ft/min}$

Explanation:

$A_1$ = Area of section 1 = $10\ \text{ft}^2$

$V_1$ = Velocity of water at section 1 = 100 ft/min

$v_1$ = Specific volume at section 1 = $4\ \text{ft}^3/\text{lbm}$

$\rho$ = Density of fluid = $0.2\ \text{lb/ft}^3$

$A_2$ = Area of section 2 = $2\ \text{ft}^2$

Mass flow rate is given by

$m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}$

The mass flow rate through the pipe is $250\ \text{lbm/min}$

As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

$m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}$

The speed at section 2 is $625\ \text{ft/min}$ .

3 0

3 years ago

Which do you think would cause the most destruction to the organisms in a food web: taking away the carnivores, taking away the

kotegsom [21]

Answer:

Explanation:

I do not have access to your diagram but based on what I know, a food web cannot sustain itself without decomposers. They are the main guys who break down dead animals, plants into organic or inorganic nutrients which are needed by the primary producers to grow. So if decomposers are not there then producers cannot produce and thus herbivores cannot live and carnovers die out as well. Hope this makes sense.

Check out: https://www.nationalgeographic.org/encyclopedia/decomposers/

6 0

3 years ago