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3 years ago

Deviations from the engineering drawing cannot be made without the approval of the

Engineering

2 answers:

NeTakaya3 years ago

8 0

Answer:

a. contractor

Explanation:

The contractor has to approve or give the sign for the drawings to be made, otherwise you can't do anything.

alexgriva [62]3 years ago

7 0

Answer:

it's option a. contractor

Explanation:

did the same quiz

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1. A screw driver with a 1.5 inch diameter handle is used to install a 1/4-20 UNC screw. Determine the circumference where the e

marishachu [46]

Explanation:

1. Circumference of the handle (where the effort is applied) is pi times diameter.

C = πd

C = 1.5π inches

C ≈ 4.71 inches

2. Mechanical advantage is the ratio of distance in over distance out.

MA = din / dout

MA = 1.5 / 0.25

MA = 6

3. Mechanical advantage is the ratio of force out over force in.

MA = Fout / Fin

6 = Fout / 10 lb

Fout = 60 lb

8 0

3 years ago

The acceleration of a particle is given by a = 2t − 10, where a is in meters per second squared and t is in seconds. Determine t

tensa zangetsu [6.8K]

Answer

given,

a = 2 t - 10

velocity function

we know,

$\dfrac{dv}{dt}=a$

$\dfrac{dv}{dt}=(2t-10)$

integrating both side

$\int dv =\int (2t -10) dt$

v = t² - 10 t + C

at t = 0 v = 3

so, 3 = 0 - 0 + C

C = 3

Velocity function is equal to v = t² - 10 t + 3

Again we know,

$\dfrac{dx}{dt}=v$

$\dfrac{dx}{dt}=(t^2-10t + 3)$

integrating both side

$\int dx =\int (t^2-10t + 3)dt$

$x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t + C$

now, at t= 0 s = -4

$-4 = \dfrac{0^3}{3}- 10\dfrac{0^2}{2} + 0 + C$

C = -4

So,

$x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4$

Position function is equal to $x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4$

8 0

4 years ago

At the inlet to the combustor of a supersonic combustion ramjet (or scramjet), the flow Mach number is supersonic. For a fuel-ai

Daniel [21]

Answer:

The inlet match number is 3.42.

Explanation:

8 0

4 years ago

Serratia marcescens bacteria are used for the production of threonine. The maximum specific oxygen uptake rate of S. marcescens

Sati [7]

Answer:

The rate of cell metabolism is limited by mass transfer since the value of maximum cell concentration obtained (38 g/l) is lower than 50 g l-1, the value planed.

Explanation:

Data

kLa = 0.17/s

Solubility of oxygen = 8 × 10^-3 kg / m^3

The maximum specific oxygen uptake rate = 4 mmol O2 / g h.

Concentration of oxygen = 0.5 × 10^-3 kg/ m^3

**The maximum cell density = 50 g/l

___________________

The calculated maximum cell concentration:

xmax= kLa · CAL*/ qo

CAL* is the solubility of oxygen in the broth and qo is the specific oxygen uptake rate

Replacing the data given

xmax= ( 0.17/s ) · (8 × 10^-3 kg / m^3) / 4 mmol O2 / g h

4 mmol O2 / g h to kg O2/ g s

$4 \frac{mmol}{gh} \frac{1 gmol}{1000mmol}\frac{1h}{3600s}\frac{32 g}{gmol} \frac{1Kg}{1000g}$

= 3.56 x 10^-3 kg O2/ g s

So then,

xmax= ( 0.17/s ) · (8 × 10^-3 kg / m^3) / 3.56 x 10^-3 o kg O2/ g s

xmax= 3. 8 x 10^4 g/ m^3 = 38 g/l

_____________________

5 0

3 years ago

Where did fossil fuels come from

Levart [38]

Any fuel such as coal, petroleum (crude oil) or natural gas that has developed within the Earth over millions of years from the decayed remains of bacteria, plants or animals

6 0

3 years ago

Read 2 more answers