Answer:
C
Step-by-step explanation:
The right triangle on the right side of the figure has a height of 6 (two same sides lengths) and a base of 3.
x is the hypotenuse (side opposite of 90 degree angle).
We can use the pythagorean theorem to find x. The pythagorean theorem tells us to square each leg (height and base) of the triangle and add it. It should be equal to the hypotenuse square.
For this triangle it means, we square 6 and 3 and add it. It should be equal to x squared. Then we can solve. Shown below:
<em>Now we can use property of radical 
to simplify:</em>
Correct answer is C
Answer:
x = -4.604
Step-by-step explanation:
Here, we want to get the value of x
We start by dividing through by 5
e^(2x + 11) = 30/5
e^(2x + 11) = 6
Writing this in natural logarithm form, we have;
ln 6 = 2x + 11
2x + 11 = 1.792
2x = 1.792-11
2x = -9.208
x = -9.208/2
x = -4.604
Answer:
(a) true
(b) true
(c) false; {y = x, t < 1; y = 2x, t ≥ 1}
(d) false; y = 200x for .005 < |x| < 1
Step-by-step explanation:
(a) "s(t) is periodic with period T" means s(t) = s(t+nT) for any integer n. Since values of n may be of the form n = 2m for any integer m, then this also means ...
s(t) = s(t +2mt) = s(t +m(2T)) . . . for any integer m
This equation matches the form of a function periodic with period 2T.
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(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:
s(a) +s(b) = s(a+b) . . . . definition of linear function
Then if a=b, you have
2s(a) = s(2a)
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(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.
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(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.
Answer:
(-5,-3)
(1,3)
Step-by-step explanation:
Solving with substitution
Set both equations to y = ...
y = x^2 + 5x - 3
----------------
y - x =2
y = x + 2
----------------
Substitute one of the Y's with the other Y = equation.
x + 2 = x ^2 + 5x -3
Set one side to 0
0 = x^2 + 4x -5
x^2 + 4x - 5 = 0
Simplify by factoring
(x-1) (x+5)
Get your X values
x-1 = 0
x = 1
x+5 = 0
x = -5
Plug in each X into one of the equations to get your Y value.
1st X
y = x + 2
y = 1 + 2
y = 3
When X = 1, Y = 3
2nd X
y = x + 2
y = -5 + 2
y = -3
When X = - 5, Y = -3
Your answers are (1,3) and (-5,-3)
Answer:
B
Step-by-step explanation:
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