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4 years ago

If a = 5 c=9 what is be

Mathematics

1 answer:

ddd [48]4 years ago

3 0

B = ac/2

45/2 = 22.5

b= 22.4

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What is the slope of these lines?<br> What is the equation of these lines?

Mashcka [7]

For both lines the slope is 5/2 or 2.5.
Since the y-intercept is zero for both, both the equations are:
y=2.5x
Or
y=5/2x

4 0

3 years ago

1 r 2 (the symbol is pi) is the formula to find the area of a

vaieri [72.5K]

Answer:

d: circle

Step-by-step explanation:

The area of a circle is pi times the radius squared (A = π r²). Learn how to use this formula to find the area of a circle when given the diameter.

3 0

3 years ago

Read 2 more answers

Meg is 6 years older than Victor. Meg's age is 2 years less than five times Victor's age. The equations below model the relation

Verdich [7]

Since no possible correct method is posted, I will suggest a couple.

Method 1: guess and check

Works well for simple problems involving integers like this one.

Victor's age must be zero or greater than one, say one.

Guess v=1, find m=v+6=7, check m=5v-2=5-2=3 no good.

we need to make v bigger

Guess v=2, find m=v+6=2+6=8, check m=5v-2=5*2-2=8 ✔

So v=2, m=8.

Method 2:

Solve the system of two equations.

since the left-hand sides is m in both equations, and since m=m, we just have to equate the right-hand sides to solve for v.

5v-2=v+6

Solve for v

5v-v = 6+2

4v=8

v=2,

so again, v=2, m=v+6=2+6=8.

6 0

4 years ago

Choose the slope of the line that passes through (2,3) and (-4,5)

Nady [450]

5-3/-4-2=-2/6 the slope of the line is -2/6. This is the case because you do y1-y2 over x1-x2. ANSWER -2/6

7 0

3 years ago

A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m

photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

Mass of the car, v1 = 1500 kg

initial speed of car = 35 miles/h

$=\dfrac{35\times 1609.34}{3600}\ m/s$

= 15.64 m/s

Initial kinetic energy of the car is given by,

$k_1\ =\ \dfrac{1}{2}.m.v_1^2$

$=\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule$

= 183606.46 J

Final velocity of car v2 = 70 miles/hour

$=\dfrac{70\times 1609.34}{3600}$

= 31.29 m/s

So, final kinetic energy of car is given by

$k_2\ =\ \dfrac{1}{2}.m.v_2^2$

$=\ \dfrac{1}{2}\times 1500\times (31.29)^2$

= 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

$\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}$

$=>\ k_2\ =\ 4k_1$

Hence, the kinetic energy will increase by 4 times.

7 0

3 years ago