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4 years ago

Amena created this stem and leaf plot to show the test scores for students in her math class.

Mathematics

2 answers:

lara [203]4 years ago

7 0

Answer:

B & C (Amena wants to show the distribution of the data & The range and set of data are too large to graph on a line plot

Step-by-step explanation:

For one I took the test and made a 100% also there are too many numbers for it to be on any other graph but also the key for the data also makes it to where its too big for other graphs also she wants to show the data and how it has grown or shrunk so she distributes her data on the graph. Thank you! :)

Tcecarenko [31]4 years ago

4 0

Answer:

Amena wants to show the distribution of the data.

The range and set of data are too large to graph on a line plot.

Step-by-step explanation:

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5/6 - 7/12? what is it

IgorLugansk [536]

Answer:

3/10

Step-by-step explanation:

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2 years ago

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Keith’s dad is 44 years old if this is 4 years less than three times Keith’s age how old is Keith

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

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4 years ago

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App 19.study

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

3 years ago

Explain how you would find the height of a rectangular prism if you know that the volume is 60 cubic cm and that the area of the

Oksi-84 [34.3K]

Base = length * width.

We know that the base has an area of 10
And 60 is the volume. Then 60 / 10 = 6 Which is the height.

7 0

3 years ago

a roller skating rink offers a special rate for birthday parties. On the samr day, a party for 10 skaters cost $107 and a party

olga nikolaevna [1]

Answer:

$119

Step-by-step explanation:

Let

x -----> the number of skaters

y -----> the cost for birthday parties

we have the points

(10,107) and (15,137)

step 1

Find the slope of the linear equation

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{137-107}{15-10}$

$m=\frac{30}{5}=6\ \frac{\$}{skater}$

step 2

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=6\\point\ (10,107)$

substitute

$y-107=6(x-10)$

step 3

Convert to slope intercept form

$y-107=6x-60$

$y=6x-60+107$

$y=6x+47$

step 4

How much would a party for 12 skaters cost?

For x=12 skaters

substitute the value of x in the equation and solve for y

$y=6(12)+47$

$y=\$119$

4 0

3 years ago