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Snezhnost [94]
4 years ago
13

A whole number consists of the digits 2, 4, 6, 8, and 0. If each digit is used only once, how many whole numbers are possible?

Mathematics
2 answers:
Tresset [83]4 years ago
6 0
Using the digits of 2, 4, 6, 8, and 0 as a number and only using them once, you could possibly have 120 different numbers. You can get this by having a choice of 5 numbers for the first digit, 4 numbers for the second digit and so on...leaving the problem of 5! (five factorial....5x4x3x2x1 = 120)
Eddi Din [679]4 years ago
4 0
120 numbers are possible. <u />You have five spots for numbers. 

_ _ _ _ _

Since each digit is used only once, there are 5 possibilities for the first digit, 4 for the next, 3 for the next, and so on. 
<u>
</u><u>5</u> <u>4</u> <u>3</u> <u>2</u> <u>1
</u><u>
</u>5 x 4 x 3 x 2 x 1 = 120




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