3 years ago

Which law of motion accounts for the following statement?

1 answer:

4 0

First, you need forces attracting the Sun and Earth toward each other. That's described by Newton's law of universal gravitation.

Then you need the description of how that force causes the planet to move in a circular path. The best choice is Newton's <em>Second law</em> of motion: F = m A .

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a sprinter starts from rest and accelerates at a rate of 0.16 ms ^-2 over a distance of 50.0 meters . How fast is the athlete tr

vlada-n [284]

Answer:

Final velocity v = 4 m/s

Explanation:

Given:

Initial velocity u = 0 m/s

Acceleration a = 0.16 m/s²

Distance s = 50 m

Find:

Final velocity v

Computation:

Using; v² = u² + 2as

v² = (0)² + 2(0.16)(50)

v² = 16 m/s

v = 4 m/s

Final velocity v = 4 m/s

7 0

3 years ago

A girl has a weight of 450 N and her feet have a total area of 0.0300 m2. Calculate the pressure her feet put on the ground.

GenaCL600 [577]

Answer:

15000N/m²

Explanation:

Given parameters:

Weight = 450N

Total area = 0.03m²

Unknown:

Pressure under her feet = ?

Solution:

Pressure is the force per unit area on a body.

Pressure = $\frac{Force }{Area}$

Weight is a type of force;

Pressure = $\frac{450}{0.03}$ = 15000N/m²

4 0

3 years ago

The metric unit for temperature is _______________.<br> a. fahrenheitb. celsiusc. secondd. liter

Nikitich [7]

The metric unit for temperature is celsius.

8 0

3 years ago

Astronauts often undergo special training in which they are subjected to extremely high centripetal accelerations. One device ha

egoroff_w [7]

The centripetal acceleration of an object is given by the relation,

$Ac =V^2/R$

where Ac = centripetal acceleration = $98 m/s^2$

R = radius of rotation = 15 m

V = speed of astronaut

Hence, $\frac{V^2}{15} =98$

solving this we get, V = 38.34 m/s

3 0

3 years ago

Read 2 more answers

A star produces 2x10^26 watts. how much energy does it lose every minutes

Step2247 [10]

Answer:

Energy loss per minute will be $120\times 10^{26}j$

Explanation:

We have given the star produces power of $2\times 10^{26}W$

We know that 1 W = 1 J/sec

So $2\times 10^{26}W=2\times 10^{26}J/sec$

Given time = 1 minute = 60 sec

So the energy loss per minute $=2\times 10^{26}\times 60=120\times 10^{26}j$

We multiply with 60 we have to calculate energy loss per minute

7 0

4 years ago