What is the speed of an object that moves from 70 m to 68 m in 14 s?
1 answer:
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The moon clock is A) (9.8/1.6)h compared to 1 hour on Earth
Explanation:
The period of a simple pendulum is given by the equation
where
L is the length of the pendulum
g is the acceleration of gravity
In this problem, we want to compare the period of the pendulum on Earth with its period on the Moon. The period of the pendulum on Earth is
where
is the acceleration of gravity on Earth
The period of the pendulum on the Moon is
where
is the acceleration of gravity on the Moon
Calculating the ratio of the period on the Moon to the period on the Earth, we find
Therefore, for every hour interval on Earth, the Moon clock will display a time of
A) (9.8/1.6)h
#LearnwithBrainly
So what you do is you use the formula shown below:
specific heat capacity = energy required / (mass * change in temperature)
here ,
energy required = 10.0°C Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C Note that "ΔT" means change in temperature
So, plugging the values into the formula, we get,
Specific heat capacity=
=
= 0.1802 cal./g°C <span>i rounded the answer to the fourth decimal point
</span>
specific heat capacity = energy required / (mass * change in temperature)
here ,
energy required = 10.0°C Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C Note that "ΔT" means change in temperature
So, plugging the values into the formula, we get,
Specific heat capacity=
=
= 0.1802 cal./g°C <span>i rounded the answer to the fourth decimal point
</span>