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Kobotan [32]
4 years ago
7

A wave pulse traveling to the right along a thin cord reaches a discontinuity where the rope becomes thicker and heavier. What i

s the orientation of the reflected and transmitted pulses? A wave pulse traveling to the right along a thin cord reaches a discontinuity where the rope becomes thicker and heavier. What is the orientation of the reflected and transmitted pulses? The reflected pulse is right-side up, and the transmitted pulse is inverted. The reflected pulse is inverted, and the transmitted pulse is right-side up. Both the reflected and transmitted pulses are inverted. Both the reflected and transmitted pulses are right-side up.
Physics
2 answers:
Talja [164]4 years ago
8 0

Answer:

the reflected wave is inverted and the transmitted wave is up

Explanation:

To answer this question we must analyze the physical phenomenon, with an wave reaching a discontinuity, we can analyze it as a shock.

Let's start when the discontinuity is with a fixed, very heavy and rigid obstacle, in this case the reflected wave is inverted, since the contact point cannot move

In the event that it collides with an object that can move, the reflected wave is not inverted, this is because the point can rise, they form a maximum at this point.

In the proposed case the shock is when the thickness changes, in this case we have the above phenomena, a part of the wave is reflected by being inverted and a part of the wave is transmitted without inverting.

The amplitude sum of the amplitudes of the two waves is proportional to the lanería that is distributed between them.

When checking the answers the correct one is the reflected wave is inverted and the transmitted wave is up

balandron [24]4 years ago
5 0

Answer:

The answer is: The reflected pulse is inverted, and the transmitted pulse is right-side up.

Explanation:

A tight end would cause reverse reflection, while an open end would cause right side reflection. Using a heavier rope would be approximately equal to this condition (tight end). It can be said that in a heavy rope, the reflection would be reversed, and the transmitted pulse is up, due to the conservation of vertical momentum.

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If a circling object is released, centrifugal force will make it travel away from the center of its original path.
9966 [12]

The answer is True. The object is thrown away from the center of its original path due its inertia. Centrifugal force acts in the opposite direction as centripetal force. Centripetal force applies towards the center of the curvature in a spinning object. Centrifugal force is considered an apparent force while centripetal force is an actual force.

5 0
3 years ago
The percent by which the fundamental frequency changed if the tension is increased by 30 percent is ? a)-20.04% b)-40.12% c)-30%
nika2105 [10]

Answer:

Percentage increase in the fundamental frequency is

d)-14.02%

Explanation:

As we know that fundamental frequency of the wave in string is given as

f_o = \frac{1}{2L}\sqrt{\frac{T}{\mu}}

now it is given that tension is increased by 30%

so here we will have

T' = T(1 + 0.30)

T' = 1.30T

now new value of fundamental frequency is given as

f_o' = \frac{1}{2L}\sqrt{\frac{1.30T}{\mu}}

now we have

f_o' = \sqrt{1.3}f_o

so here percentage change in the fundamental frequency is given as

change = \frac{f_o' - f_o}{f_o} \times 100

% change = 14.02%

3 0
3 years ago
until a train is a safe distance from the station, it must travel at 5 m/s. once the train is on open track, it can speed up to
MatroZZZ [7]

Answer:

5 meters per second squared

Explanation:

We calculate the acceleration using the formula:

a = (vf - vi) / t

where "vf" is the final velocity, "vi" the initial velocity, and "t" the time it took to change from the initial velocity to the final one.

In our case:

a = (45 - 5) / 8 = 40 / 8 = 5 m/s^2

4 0
4 years ago
If the area of a concrete slap weighing 300n is 400cm2 ,how much pressure can it apply when kept on the ground
aleksklad [387]

Answer:

7500 N/m²

Explanation:

From the question given above, the following data were obtained:

Force (F) = 300 N

Area (A) = 400 cm²

Pressure (P) =?

Next, we shall convert 400 cm² to m². This can be obtained as follow:

1×10⁴ cm² = 1 m²

Therefore,

400 cm² = 400 cm² × 1 m² / 1×10⁴ cm²

400 cm² = 0.04 m²

Finally, we shall determine the pressure. This can be obtained as follow:

Force (F) = 300 N

Area (A) = 0.04 m²

Pressure (P) =?

P = F/A

P = 300 / 0.04

P = 7500 N/m²

3 0
3 years ago
Pls help quickly
emmasim [6.3K]

Answer: frosted glass

Explanation:

8 0
3 years ago
Read 2 more answers
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