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lesantik [10]
3 years ago
7

108.95 g/mol, C3H2Cl2 Express your answer as a chemical formula.​

Chemistry
1 answer:
fredd [130]3 years ago
6 0

Answer:

gchxlhxhkxhkxohxhochlc

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Magnesium burns in air with a dazzling brilliance to produce magnesium oxide: 2 Mg(s) + O2(g) → 2 MgO(s) How many moles of O2 ar
TEA [102]

Answer:

1.05 mols of O2 gas

Explanation:

For this type of problem, it's important to understand what the balanced Chemical equation tells us:

<h3><u>Balanced Chemical equations</u></h3>

Let's look at the balanced chemical equation:

2Mg(s)+O_2(g)-- > 2MgO(s)

This equation two sides of the reaction arrow.  On the left are the reactants (things you start with, and that react during the chemical reaction), and on the right side are products (things that are produced during the chemical reaction that you end with).

The numbers in front of each compound tell how many of molecules are involved for a full reaction without anything left over.  A "mol" is a large quantity (6.022*10^{23}), in this case, of molecules , since it's unlikely you're only taking a single molecule of each substance (it would be so tiny, you wouldn't even know you were doing the reaction).

So,for every 2 moles of Magnesium used, we'll also need 1 mole of Oxygen, and it will produce 2 moles of Magnesium Oxide.

In a way, during the reaction it's almost like 2 moles of Magnesium is equal to 1 mole of Oxygen and is equal to 2 moles of Magnesium Oxide:

2 mol Mg(s)=1mol O_2(g)=2molMgO(s)

From here, we can build some unit ratios, to convert between the known quantity of moles we have, and find the unknown quantity of moles that are requested.

<h3><u>Finding the right unit ratio</u></h3>

We know that we are looking at 2.10 mol of Magnesium, so we want a unit ratio with moles of Mg on the bottom.  <u>We want to find moles of O2</u>, <u>so we want a unit ratio of moles of O2 on top</u>.

The unit ratio we want is the middle part of the equation, divided by the left part of the equation.

2 mol Mg(s)=1mol O_2(g)\\\frac{2 mol Mg(s)}{2 mol Mg(s)}=\frac{1mol O_2(g)}{2 mol Mg(s)}\\1=\frac{1mol O_2(g)}{2 mol Mg(s)}

Since this quantity is 1, it is a unit ratio and can be multiplied to other things to change their units (for this problem).

<h3><u>Finding the answer</u></h3>

Starting with what we know, and multiplying by our unit ratio:

2.10 mol Mg(s)*\frac{1mol O_2(g)}{2 mol Mg(s)}=1.05mol O_2(g)

Notice that the units from the first quantity cancel with the units on the bottom of the fraction, leaving only the unit on top of the fraction ... the exact units we wanted!

So, 1.05mols of O2 would be consumed during the reaction if exactly 2.10moles of Magnesium are burned.

4 0
3 years ago
In any energy pyramid, only ________ of the available energy is passed from one level to the next.
ddd [48]
10%
At each trophic level only small proportion of energy is transferred to the next level
3 0
4 years ago
Which best defines a service? a task that is performed in exchange for payment an object that is acquired a plan that is execute
tatiyna

Answer:

a task that is performed for payment

Explanation:

all of the other answers do not pertain to the question

8 0
3 years ago
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Which description best characterizes the motion of particles in a solid?
antoniya [11.8K]

The particles in a solid are tightly packed and locked in place. Although we cannot see it or feel it, the particles are vibrating in place.

As these molecules heat up, they will vibrate more vigorously, and will eventually turn to water, then gas.

5 0
3 years ago
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What is the classified matter of gold​
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Gold is classified as a Solid
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