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2 years ago

108.95 g/mol, C3H2Cl2 Express your answer as a chemical formula.

Chemistry

1 answer:

fredd [130]2 years ago

6 0

Answer:

gchxlhxhkxhkxohxhochlc

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When you have finished adding the necessary amount of NaOH to your beaker, what color will the litmus paper turn?

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Answer: The red litmus paper turns blue on dipping in NaOH solution.

Explanation:

Litmus paper is the indicator that detects the nature of the solution, whether it is acidic or basic.

There are 2 types of litmus paper:

Red litmus paper: This paper will turn blue if it is dipped in basic solution and will remain as such if it is dipped in acidic solution.
Blue litmus paper: This paper will turn red if it is dipped in acidic solution and will remain as such if it is dipped in basic solution.

NaOH is a strong base, so when a red litmus paper is dipped in the beaker having necessary amount of NaOH, the red litmus paper turns into blue.

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3 years ago

Identify the group number of following oxides/hydrides in Mendeleev

Ivan

Answer:

See explanation

Explanation:

The oxides or hydrides are formed by exchange of valency between the two atoms involved. The group of the atom bonded to oxygen or hydrogen in the binary compound can be deduced by considering the subscript attached to the oxygen or hydrogen atom.

Now let us take the journey;

R2O3- refers to an oxide of a group 13 element, eg Al2O3

R2O - refers to an oxide of group a group 1 element e.gNa2O

RO2 - refers to an oxide of a group 14, 15 or 16 element such as CO2, NO2 or SO2

RH2 - refers to the hydride of a group 12 element Eg CaH2

R2O7 - refers to an oxide of a group 17 element E.g Cl2O7

RH3- refers to a hydride of a group 13 element E.g AlH3

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3 years ago

How many atoms are present in a 0.600- mole sample of gold?

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2 years ago

The density of water is 1.00 g/ml at 4°c. how many water molecules are present in 2.36 ml of water at this temperature?

spin [16.1K]

Mass of 1 ml of water 1 g as density of water 1.00 g/ml at 4° C. So, mass of 2.36 ml of water $\frac{1}{2.36}$ g= 0.423 g.

Molecular mass of water is 18 g which indicates 18 g water contains 6.023 X $10^{23}$ number of water molecules. So, 0.423 g of water contains $\frac{6.023 X 10^{23} X 0.423 }{18} g$ = 0.141 X $10^{23}$ number of water molecules= 1.41 X $10^{22}$ number of water molecules.

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3 years ago

108.95 g/mol, C3H2Cl2 Express your answer as a chemical formula.​

108.95 g/mol, C3H2Cl2 Express your answer as a chemical formula.