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icang [17]
3 years ago
15

Calculate the amount of heat, in kilojoules, required to turn solid ammonia at -78 degrees Celsius to gaseous ammonia at standar

d temperature
Chemistry
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

132

Explanation:

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In the reaction of nitrogen gas with oxygen gas to produce nitrogen oxide, what is the effect of adding more oxygen gas to the i
Alborosie
<h3>Answer:</h3>

The Equilibrium would shift to produce more NO

<h3>Explanation:</h3>

The reaction is;

N₂(g) + O₂(g) ⇆ 2NO(g)

  • When a reaction is at equilibrium then the forward reaction rate will be equivalent to the reverse reaction rate. Additionally, the concentration of the reactants and products are the same.
  • From Le Chatelier's principle, additional reactants favor the formation of more products while additional products favor the formation of more reactants.
  • For example, when more oxygen is added then more Nitrogen (II) oxide will be formed.
  • Oxygen is a reactant and when increased it favors forward reaction which leads to the formation of more NO which is the product.

3 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is
Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0
3 years ago
Describe how naturally<br> acidic rainwater can affect a<br> mountain of limestone.
Hitman42 [59]
The naturally acidic rainwater will erode the limestone mountin over time
6 0
3 years ago
Give examples to three solutions you commonly use and identify the solvent and solutes that make it each up.
8_murik_8 [283]
Mouthwash:
solvent - water
solute - alcohols

vinegar:
solvent - water
solute - acetic acid

bleach:
solvent - water
solute - sodium hypochlorite

hope this helps!!

8 0
3 years ago
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What solute particles are present in an aqueous solution of CH3COCH3?
Anuta_ua [19.1K]
PE, GO, XY - I am  probably wrong xoxoxoxoxxo
4 0
3 years ago
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