Perimeter = a + b + c = 30
Area = 1/2 x a x b = 30
Multiples of 30: 2, 3, 5, 6, 10, 12, 15
For perimeter c = 30- (a+b)
C= sqrt( a^2 + b^2)
Using the possible combinations of the above:
5 and 12:
C = sqrt(5^2 + 12^2) = 13
5 + 12 + 13 = 30 for the perimeter
Area = 1/2 x 5 x 12 = 30
The sides are 5, 12 and 13 cm
Answer:
259.6 ft/sec
Step-by-step explanation:
it is a universal standard that acceleration due to gravity is 32ft/sec^2.
Now it can be verified by equation,
V(f) = V(i)+at (1st equation of motion derived by Newton's three laws of motion)
where,
V(f) is final velocity
V(i) is initial velocity
a is acceleration which is constant and have value 32ft/sec^2
t is time which is given as 7.8 seconds
In the given case, initial velocity that is V(i) will be 0ft/sec. Because, on dropping, object will start to move under the influence of gravity from zero speed.
So,
V(f) = 0 +(32) (7.8)
V(f) = 249.6 ft/sec
Now the condition is given that you have to add a constant 10 to the answer.
so, V(f) = 249.6 + 10
V(f) = 259.6 ft/sec
Answer:
17
Step-by-step explanation:
Answer:
one side is 40 other is 50
Step-by-step explanation:
perimeter=180cm
let one side=length=x
Acc. to condition:
other side=width=x+10 (one side exceed other by 10)
perimeter= 2(length+width)
subtitue all values given above:
180=2(x+x+10)
180=2(2x+10)
2x+10=180/2
2x+10=90
2x=90-10
2x=80
x=40
now
lenght=x=40cm
width=x+10=40+10
width=50cm
Answer:
∠BAC = 105°
Step-by-step explanation:
2(5x) = 9x+21
10x = 9x+21
reduce:
x = 21
∠BAC = 5x = 105°
