To solve for this, we need to find for the value of x
when the 1st derivative of the equation is equal to zero (or at the
extrema point).
So what we have to do first is to derive the given
equation:
f (x) = x^2 + 4 x – 31
Taking the first derivative f’ (x):
f’ (x) = 2 x + 4
Setting f’ (x) = 0 and find for x:
2 x + 4 = 0
x = - 2
Therefore the value of a is:
a = f (-2)
a = (-2)^2 + 4 (-2) – 31
a = 4 – 8 – 31
a = - 35
3x - 3 = 2x
Add 3 on both sides
3x - 3 + 3 = 2x + 3
3x = 2x + 3
Subtract 2x on both sides
3x - 2x = 2x + 3 - 2x
3x - 2x = 3
x = 3
So, your final answer is x = 3.
Answer:
<h2>f(x) = 3x + 4</h2>
Step-by-step explanation:
f(x + 1) = 3x - 7
f(x) = f(x + 1 - 1) = 3(x - 1) + 7 = 3x - 3 + 7 = 3x + 4
Check
f(x) = 3x + 4
f(x + 1) = 3(x + 1) + 4 = 3x + 3 + 4 = 3x + 7 CORRECT
Answer:
240
Step-by-step explanation:
12 times 2 is 24
24 times 10 is 240
Have a nice day
Ok, I am ready, what are the questions.
Tell me in the comment section
