Answer:
initial speed is 13.36 m/s
Explanation:
given data
mass = 2 kg
velocity = 10 m/s
distance = 20 m
friction= 0.2
to find out
initial speed
solution
we find first friction force that is
friction force = friction ×mass×g ...........1
put here value
friction force = 0.2 × 2 × 9.81
friction force = 3.924 N
here a will be -ve due to friction
- friction force = mass × acceleration
acceleration = - friction force / mass
acceleration = - 3.924 / 2
acceleration = - 1.962 m/s²
and we know velocity formula that is
V² = V(i)² + 2as
put here value
10² = V(i)² + 2(-1.962)(20)
V(i) = 13.36
so initial speed is 13.36 m/s
Answer:
It's True...................
The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. F = ma; a = F/m. This means that Force over the mass. In order to improve the acceleration without redesigning is that the company has to improve the force assuming that the mass is still the same.
Answer:
a) equal 1, b) less than 1
Explanation:
a) the electric force is given by
Fe = q E
The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative
Proton
Fp = qE
Electron
Fe = - q E
Fp / Fe = -1
If we do not take into account the sign the relationship is equal to one (1)
b) to calculate the force we use Newton's second law
F = ma
qE = m a
a = q E / m
The mass of the proton much greater than the mass of the electron
ap = q E / 
ae = - q E / 
ap / ae = /
= /1600 =1/1600
It is much smaller than 1
Answer:
8
Explanation:
Applying,
v = λf................ Equation 1
Where v = velocity/ speed of the wave, λ = wave length of the wave, f = number of waves the person surf in one seconds.
make f the subject of the equation
f = v/λ............ Equation 2
From the question,
Given: v = 1.6 m/s, λ = 24 m
Substitute these values into equation 2
f = 1.6/24
f = 0.0667 wave/seconds.
If,
in one seconds, the person surf a total wave crest of 0.0667
Therefore,
in one hours, he will surf a total wave crest of (0.0667×60×60) = 240 waves crest
He rides for every 30th wave crest,
Hence,
number of wave crest the person surf in one hour = 240/30 = 8
