Answer:
The potential energy (P.E) at the top is 392 J
The kinetic energy (K.E) at the top is 0 J
The potential energy (P.E) at the halfway point is 196 J.
The kinetic energy (K.E) at the halfway point is 196 J.
Explanation:
Given;
mass of the rock, m = 2 kg
height of the cliff, h = 20 m
speed of the rock at the halfway point, v = 14 m/s
The potential energy (P.E) and kinetic energy (K.E) when its at the top;
P.E = mgh
P.E = (2)(9.8)(20)
P.E= 392 J
K.E = ¹/₂mv²
where;
v is velocity of the rock at the top of the cliff = 0
K.E = ¹/₂(2)(0)²
K.E = 0
The potential energy (P.E) and kinetic energy (K.E) at the halfway point;
P.E = mg(¹/₂h)
P.E = (2)(9.8)(¹/₂ x 20)
P.E = 196 J
K.E = ¹/₂mv²
where;
v is velocity of the rock at the halfway point = 14 m/s
K.E = ¹/₂(2)(14)²
K.E = 196 J.
Answer:
It is half the field strength at 0.5cm
Explanation:
Answer:
Middle childhood
Explanation:
<em>Middle childhood happens around ages 6 to 12,</em> is a stage in the human development characterized by the steady rate of physical growth of the individual in contrast with the fast rate of emotional, cognitive and emotional development that will prepare them for future stages (adolescence and adulthood).
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Answer:
The standard form of a straight line is
y = m x + b where m is the slope
m = (y2 - y1) / (x2 - x1)
if the ordinate is formed by v instead of y then
m = (v2 - v1) / (x2 - x1) normally for constant acceleration the slope is
(v2 - v1) / (t2 - t1) = a = m