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3 years ago

An object on the moon will weigh 1/6th of what it does on earth but have the same mass. Why is that?

Physics

1 answer:

elena55 [62]3 years ago

8 0

Answer:

Because the weight depends of the gravity

Explanation:

This is because weight and mass are different, in order to better understand this problem we will apply an example with real values, which will help us to determine a person's weight.

A man has a mass of 80 [kg] on Earth when measuring his weight he realizes that it is 784.9 [N] and on the moon it is 130.8 [N]

On Earth

$g_{e} = 9.81[m/s^2]\\g_{m} = 1.635[m/s^2]$

Where:

g = gravity

Weight on the moon

Wm = 80 * 1.635

Wm = 130.8[N]

Weight on the earth

We = 80 * 9.81

We = 784.8[N]

In this way we can see that the weight depends on the gravity of where the person is located.

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A truck is moving around a circular curve at a uniform velocity of 13 m/s. If the centripetal force on the truck is 3,300 N and

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Answer: Option B.

Since here the truck is moving on a circular track, it will experience centripetal force.

F(centripetal) = m × acc
or
$r = \frac{m v^{2}}{F}$

where r is the radius of the track.
m is the mass of truck
v is the speed of the truck.
Given: v = 13 m/s
m = 1,600 kg
F = 3300 Newton

To find = radius of track=?
$r = \frac{m v^{2} }{F}$
$r = \frac{1600*13*13}{3300}$
r = 81.94 m
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3 years ago

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I = 2.0 x 10^-4 C / 5.0 x 10^-5 s
I = 4 A or 4.0 x 10^0 A

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4 years ago

Consider a golf club hitting a golf ball. To a good approximation, we can model this as a collision between the rapidly moving h

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Answer:

1. 8.0kg * m/s

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3 years ago

A 20 kg truck drives in a circle of radius 4 m at 10m/s. What is the

Tems11 [23]

Mass=m=20kg
Radius=r=4m
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We know

$\boxed{\sf F_c=\dfrac{mv^2}{r}}$

$\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}$

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$\\ \sf\longmapsto F_c=\dfrac{2000}{4}$

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3 years ago

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4 years ago