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Paraphin [41]
3 years ago
11

An object on the moon will weigh 1/6th of what it does on earth but have the same mass. Why is that?

Physics
1 answer:
elena55 [62]3 years ago
8 0

Answer:

Because the weight depends of the gravity

Explanation:

This is because weight and mass are different, in order to better understand this problem we will apply an example with real values, which will help us to determine a person's weight.

A man has a mass of 80 [kg] on Earth when measuring his weight he realizes that it is 784.9 [N] and on the moon it is 130.8 [N]

<u>On Earth</u>

<u />

g_{e} = 9.81[m/s^2]\\g_{m} = 1.635[m/s^2]

Where:

g = gravity

<u>Weight on the moon</u>

<u />

Wm = 80 * 1.635

Wm = 130.8[N]

<u>Weight on the earth</u>

<u />

We = 80 * 9.81

We = 784.8[N]

<u />

In this way we can see that the weight depends on the gravity of where the person is located.

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natima [27]

Answer:

The potential energy (P.E) at the top is 392 J

The kinetic energy (K.E) at the top is 0 J

The potential energy (P.E) at the halfway point is 196 J.

The kinetic energy (K.E) at the halfway point is 196 J.

Explanation:

Given;

mass of the rock, m = 2 kg

height of the cliff, h = 20 m

speed of the rock at the halfway point, v = 14 m/s

The potential energy (P.E) and kinetic energy (K.E) when its at the top;

P.E = mgh

P.E = (2)(9.8)(20)

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K.E = ¹/₂mv²

where;

v is velocity of the rock at the top of the cliff = 0

K.E = ¹/₂(2)(0)²

K.E = 0

The potential energy (P.E) and kinetic energy (K.E) at the halfway point;

P.E = mg(¹/₂h)

P.E = (2)(9.8)(¹/₂ x 20)

P.E = 196 J

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where;

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K.E = ¹/₂(2)(14)²

K.E = 196 J.

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2 years ago
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Answer:

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Explanation:

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Answer:

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I hope you find this information useful and interesting! Good luck!

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